Answer:
The new volume will be 5.80 L
Explanation:
Step 1: Data given
The initial volume = 29.0 L
The initial pressure = 562 torr = 562 /760 atm = 0.739474 atm
The pressure changes to 2810 torr = 2810 /760 atm = 3.697368 atm
The temperature and number of moles will not change
Step 2: Calculate the new volume
P1*V1 = P2*V2
⇒With P1 = the initial pressure = 0.739474 atm
⇒with V1 = the initial volume = 29.0 L
⇒with P2 = the increased pressure = 3.697368 atm
⇒with V2 = The new volume = TO BE DETERMINED
0.739474 atm * 29.0 L = 3.697368 atm * V2
V2 = 5.80 L
OR
562 torr * 29.0 L = 2810 torr * V2
V2 = 5.80 L
The new volume will be 5.80 L
Answer:
a) Endothermic
b) T₂ = 53.1 ºC
Explanation:
a) We are told that when the ammonium nitrate dissolves in water the pack gets cold so the system is absorbing heat from the surroundings and by definition it is an endothermic process.
b) Recall that the heat, Q, is given by the formula:
Q = mcΔT where m is the mass of water,
c is the specific heat of water, and
ΔT is the change in temperature
We can determine the value for Q since we are given the heat of solution for the ammonium nitrate. From there we can calculate ΔT and finally answer our question.
Molar mass NH₄NO₃ = 80.04 g/mol
moles NH₄NO₃ = 50.0 g/ 80.04 g/mol = 0.62 mol
Q = 25.4 kJ/mol x 0.62 mol = 15.87 kJ = 15.87 kJ x 1000 J = 1.59 x 10⁴ J
Q = mcΔT ⇒ ΔT = Q/mc
ΔT = 1.59 x 10⁴ J/ (135 g x 4.184 J/gºC ) = 28.1 ºC
T₂- T₁ = ΔT ⇒ T₂ = ΔT + T₁ = 28.1 ºC +25.0 ºC = 53.1 ºC
Starch is a polysaccharides which is made up of a long chain of glucose. The sub units that for starch are GLUCOSE. The long chains of glucose in starch are connected by alpha 1,4 linkages. The simplest starch in existence is amylose.
The correct answer would b C
