When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 2400 k is equal to 1.22×105

Question

MaRussiya [10]

3 years ago

14

When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 2400 k is equal to 1.22×105

j/mol. calculate the equilibrium constant at 2400 k .?

Chemistry

2 answers:

Alona [7] · Answer 1 · 2022-05-10T22:25:52+03:00

The equilibrium constant of a reaction is related the Gibbs free energy in a natural logarithm relationship. It is expressed as:

G = - RT ln K

where R is 8.314 and T is the temperature. From this, we can easily calculate for the change in the equilibrium constant at different temperature.

<span>1.22×105 = - 8.314 (2400) ln K
K = 2.21x10^-3</span>

rosijanka [135] · Answer 2 · 2022-05-10T20:06:24+03:00

rosijanka [135]3 years ago

6 0

When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 2400 k is equal to 1.22×105j/mol, then the equilibrium constant at 2400 k is 2.21×10−3. The answer to the statement is 2.21×10−3.