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MaRussiya [10]
3 years ago
14

When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 2400 k is equal to 1.22×105

j/mol. calculate the equilibrium constant at 2400 k .?
Chemistry
2 answers:
Alona [7]3 years ago
7 0
The equilibrium constant of a reaction is related the Gibbs free energy in a natural logarithm relationship. It is expressed as:

G = - RT ln K

where R is 8.314 and T is the temperature. From this, we can easily calculate for the change in the equilibrium constant at different temperature.

<span>1.22×105 = - 8.314 (2400) ln K
K = 2.21x10^-3</span>
rosijanka [135]3 years ago
6 0
When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 2400 k is equal to 1.22×105j/mol, then the equilibrium constant at 2400 k is 2.21×10−3. The answer to the statement is 2.21×10−3.
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bearhunter [10]

Answer:

PCl₅ because a subscript indicates 5 chlorine atoms.

Explanation:

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Use the periodic table to find the molar mass of
Naddika [18.5K]

I can give you a clue of getting mass. if it is the atomic number is even multiply by 2 but if the atomic number is odd multiply by 2 and add 1

sodium atomic number = 11 so mass = 11*2 +1 = 23

oxygen. atomic number = 8 so mass = 8*2 = 16

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3 0
3 years ago
What volume of 0.4567 m h2so4 is required to neutralize 30.00 ml of 0.3210 m naoh?
sertanlavr [38]
Answer is: volume of H₂SO₄ is 42.1 mL.<span>
Chemical reaction: H</span>₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.<span>
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V(NaOH) = 30 mL </span>÷ 1000 mL/L <span>= 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
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n(H</span>₂SO₄) = 0,01926 mol.<span>
V(H</span>₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).<span>
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3 0
3 years ago
2) If I have an unknown quantity (# of moles) of gas at a pressure of 32 atm, a volume of 70 L, and a temperature of 25˚C. How m
astra-53 [7]

Answer:

91.5 mol

Explanation:

Volume of gas = 70 L

Temperature = 25°C

Pressure = 32 atm

Moles of gas  = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

25+273.15 = 298.15 K

By putting values,

32 atm × 70 L = n ×0.0821 atm.L /mol.K × 298.15 K

2240 atm.L = n ×24.48 atm.L /mol

n = 2240 atm.L / 24.48  atm.L /mol  

n = 91.5 mol

3 0
3 years ago
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