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MaRussiya [10]
3 years ago
14

When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 2400 k is equal to 1.22×105

j/mol. calculate the equilibrium constant at 2400 k .?
Chemistry
2 answers:
Alona [7]3 years ago
7 0
The equilibrium constant of a reaction is related the Gibbs free energy in a natural logarithm relationship. It is expressed as:

G = - RT ln K

where R is 8.314 and T is the temperature. From this, we can easily calculate for the change in the equilibrium constant at different temperature.

<span>1.22×105 = - 8.314 (2400) ln K
K = 2.21x10^-3</span>
rosijanka [135]3 years ago
6 0
When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 2400 k is equal to 1.22×105j/mol, then the equilibrium constant at 2400 k is 2.21×10−3. The answer to the statement is 2.21×10−3.
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Answer:

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Explanation:

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allsm [11]

Answer:

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8 0
3 years ago
A hypothetical AX type of ceramic material is known to have a density of 3.55 g/cm3 and a unit cell of cubic symmetry with a cel
postnew [5]

Explanation:

For AX type ceramic material, the number of formula per unit cells is as follows.

         \rho = \frac{n'(A_{c} + A_{A})}{V_{C}N_{A}}

or,     n' = \frac{\rho a^{3}N_{A}}{(A_{c} + A_{A})}

where,   n' = no. of formula units per cell

           A_{c} = molecular weight of cation = 90.5 g/mol

           A_{a} = molecular weight of anion = 37.3 g/mol

          V_{c} = volume of cubic cell = 3.55 g/cm^{3}

           a = edge length of unit cell = 3.9 \times 10^{-8} cm

        N_{A} = Avogadro's number = 6.023 \times 10^{23}

          \rho = density = 3.55 g/cm^{3}

Now, putting the given values into the above formula as follows.

           n' = \frac{\rho a^{3}N_{A}}{(A_{c} + A_{A})}

                      = \frac{3.55 g/cm^{3} \times (3.9 \times 10^{-8})^{3} \times 6.023 \times 10^{23}}{(90.5 + 37.3)}

                     = 0.9

                    = 1 (approx)

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3 0
3 years ago
How to balance this equation KClO4 → KCl + ?O2(g) and what type of reaction occurs?
Ivahew [28]

Explanation:

here is the answer to your question

7 0
3 years ago
(a) Calculate the mass percentage of NaCl in a solution containing 1.50 g of NaCl in 50.0 g of water. (b) A commercial bleaching
stepan [7]

Answer:

a) 2.91%

b) 90.5 grams

Explanation:

Mass percentage is

mass%=\frac{massofsoluteX100}{massofsolute+massofsolvent}

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b) the mass percent of NaOCl = 3.62 %

It means the mass of NaOCl in 100g of bleaching solution  3.62 g

so mass of NaOCl in 2.50kg = 0.0905 kg = 90.5g

7 0
3 years ago
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