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Fudgin [204]
3 years ago
10

Determine the temperature change when 150. G block of gold is supplied with 1.00 • 10 ^3 J of heat

Chemistry
1 answer:
IceJOKER [234]3 years ago
8 0

Answer:

∇T = 51.68°C

Explanation:

Mass = 150g

Heat Energy (Q) = 1.0*10³J

Change in temperature ∇T = ?

Q = mc∇T

Q = heat energy

M = mass

C = specific heat capacity of the gold = 0.129j/g°C

∇T = change in temperature

Q = Mc∇T

1.0*10³ = 150 * 0.129 * ∇T

1000 = 19.35∇T

Solve for ∇T

∇T = 1000 / 19.35

∇T = 51.679°C = 51.68°C

The change in temperature of gold was 51.68°C

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Q = M*C*ΔT 

when we have M ( the mass of water) = 200 g 

and C ( specific heat capacity ) of water = 4.18 J/gC

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 ∴ the amount of heat which be added and absorbed to raise the temp from 24°C to 100°C is = 63536 J


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