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Sergio039 [100]
4 years ago
5

2. What is the final velocity of an object that is traveling at 5.0 m/s and accelerates at

Physics
1 answer:
Elena L [17]4 years ago
3 0

Answer:

22.74 m/s

Explanation:

u= 5.0

a= 2.4

t= 7.39

Therefore the final velocity can be calculated as follows

v = u + at

v= 5 + 2.4(7.39)

v= 5 + 17.736

v= 22.74 m/s

Hence the final velocity of the object is 22.74 m/s

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You and your friend Peter are putting new shingles on a roof pitched at 21∘. You're sitting on the very top of the roof when Pet
Marat540 [252]

Answer:

3.69 m/s

Explanation:

Forces :

mgsin Θ - mumgcosΘ = ma  

g x sinΘ  - mu x g x cosΘ  = a

9.8 x sin 21 - 0.53 x 9.8 x cos 21 = a

a = -1.337 m/s²

so you have final velocity = 0 m/s

initial velocity = ? m/s

Given d = 5.1 m

By kinematics

vf² = vo² + 2ad

0 = vo² + 2 x -1.337*5.1

vo = 3.69 m/s

8 0
3 years ago
A 10-kilogram bicycle is traveling at a speed of 2m/s. what is the bike's kinetice energy?
madam [21]
The kinetic energy of an object of mass m moving with speed v is given by:
K= \frac{1}{2}mv^2
For the bicycle in our problem, m=10 kg and v=2 m/s, so the kinetic energy is
K= \frac{1}{2}(10 kg)(2 m/s)^2=20 J
4 0
3 years ago
Who ever answers all these questions they"ll get brain list How exactly did life begin? ... Why do we dream? ... Is there a patt
Ronch [10]

Answer: 1.

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8.thats a bit hard if i can ill find and comment down below

3 0
3 years ago
Suppose you observed the equation for a traveling wave to be y(x, t) = A cos(kx − ????t), where its amplitude of oscillations wa
OLga [1]

Answer:

<h2>15m/s</h2>

Explanation:

The equation for a traveling wave as expressed as y(x, t) = A cos(kx − \omegat) where An is the amplitude f oscillation, \omega is the angular velocity and x is the horizontal displacement and y is the vertical displacement.

From the formula; k =\frac{2\pi x}{\lambda} \ and \ \omega = 2 \pi f where;

\lambda \ is\ the \ wavelength \ and\ f \ is\ the\ frequency

Before we can get the transverse speed, we need to get the frequency and the wavelength.

frequency = 1/period

Given period = 2/15 s

Frequency = \frac{1}{(2/15)}

frequency = 1 * 15/2

frequency f = 15/2 Hertz

Given wavelength \lambda = 2m

Transverse speed v = f \lambda

v = 15/2 * 2\\\\v = 30/2\\\\v = 15m/s

Hence, the transverse speed at that point is  15m/s

8 0
3 years ago
The magnetic north pole changes location but the geographic north pole does not true or false
a_sh-v [17]
The North Magnetic Pole is the point on the surface of Earth's Northern Hemisphere at which the planet's magnetic field points vertically downwards (in other words, if a magnetic compass needle is allowed to rotate about a horizontal axis, it will point straight down). There is only one location where this occurs, near (but distinct from) the Geographic North Pole and the Geomagnetic North Pole. So yes true
3 0
3 years ago
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