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Oliga [24]
3 years ago
11

The figure above shows the net force exerted on an object as a function of the position of the object. The object starts from re

st at position x = 0 m and acquires a speed of 3.0 m / s after traveling the distance of 0.090 m shown above. What is the mass of the object?

Physics
1 answer:
weqwewe [10]3 years ago
5 0

Answer:

0.06 Kg

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 3.0 m/s

Distance (s) = 0.09 m

Net Force (F) = 3 N

Mass (m) =?

Next, we shall determine the acceleration of the object. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 3.0 m/s

Distance (s) = 0.09 m

Acceleration (a) =?

v² = u² + 2as

3² = 0² + (2 × a × 0.09)

9 = 0 + 0.18a

9 = 0.18a

Divide both side by 0.18

a = 9 / 0.18

a = 50 m/s²

Finally, we shall determine the mass of the object. This can be obtained as follow:

Net Force (F) = 3 N

Acceleration (a) = 50 N

Mass (m) =?

F = ma

3 = m × 50

Divide both side by 50

m = 3 / 50

m = 0.06 Kg

Therefore, the mass of the object is 0.06 Kg

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Law Incorporation [45]

The figure mentioned on the question is in the attachment.

Answer: a) P_{x} = - 38.35N

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c) F_{f} = 27.45 N

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Explanation: A block on an inclined plane has 3 forces acting on it:

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Since the plane is inclined, Normal Force is equal the y-component of the force due to gravity and Force of friction and the x-component of the force due to gravity are opposite forces.

The second attachment ilustrate the forces acting on the block.

Calculating:

A) The magnitude of the x-component of Force due to gravity:

According to the second image:

P_{x} = P.sinθ

P_{x} = 5.9.8.sin(36.8)

P_{x} = - 38.35 N

B) F_{N} = P_{y} = m.g.cosθ

F_{N} = 5.9.8.cos(36.8)

F_{N} = 30.5 N

C) F_{f} = 0.9.30.5

F_{f} = 27.45 N

D) For the acceleration, use Newton's Law: F_{R} = m . a

If there is movement, it is only on x-axis, so the net force is:

P_{x} - F_{f}  = m.a

- 38.35 - 27.45 = 5a

a = - 13.16 m/s²

The value of acceleration shows there is <u>no</u> <u>movement</u> on the x-axis due to the friction.

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a college student produces about 100 kcal of heat per hour on the average what is the rate of energy production and joules
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Given:

Amount of heat produced = 100 kcal per hour

Let's find the rate of energy production in joules.

We know that:

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1 kcal = 4.184 Joules

To find the rate of energy production in Joules, we have:

\begin{gathered} Rate=100\ast4.184 \\  \\ \text{Rate}=418.4\text{ KJ/hour} \end{gathered}

Therefore, the rate of energy production in joules is 418.4 kJ/h which is equivalent to 418400 Joules

ANSWER:

418.4 kJ/h

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1 year ago
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<h2>Relationship Between Frequency and Period</h2>

The frequency and the period are inversely proportional.

f=\dfrac{1}{T} where T is the period

<h2>Solving the Question</h2>

We're given:

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Because the frequency and the period are reciprocals of each other, we can find the period of the sound by finding the reciprocal of the frequency:

T=\dfrac{1}{1000}

<h2>Answer</h2>

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