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Oliga [24]
3 years ago
11

The figure above shows the net force exerted on an object as a function of the position of the object. The object starts from re

st at position x = 0 m and acquires a speed of 3.0 m / s after traveling the distance of 0.090 m shown above. What is the mass of the object?

Physics
1 answer:
weqwewe [10]3 years ago
5 0

Answer:

0.06 Kg

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 3.0 m/s

Distance (s) = 0.09 m

Net Force (F) = 3 N

Mass (m) =?

Next, we shall determine the acceleration of the object. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 3.0 m/s

Distance (s) = 0.09 m

Acceleration (a) =?

v² = u² + 2as

3² = 0² + (2 × a × 0.09)

9 = 0 + 0.18a

9 = 0.18a

Divide both side by 0.18

a = 9 / 0.18

a = 50 m/s²

Finally, we shall determine the mass of the object. This can be obtained as follow:

Net Force (F) = 3 N

Acceleration (a) = 50 N

Mass (m) =?

F = ma

3 = m × 50

Divide both side by 50

m = 3 / 50

m = 0.06 Kg

Therefore, the mass of the object is 0.06 Kg

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A boy lifted a 50 newton rock 1 meter. How much work was done?
dem82 [27]

Answer:

The answer is 50 Nm

Explanation:

<h3><u>Given</u>;</h3>
  • Applied Force = 50 Newton
  • Total Displacement = 1 meter
<h3><u>To </u><u>Find</u>;</h3>
  • Work done = ?

Here,

W = F • d

W = 50 • 1

W = 50 Nm

Thus, Work done is 50 Nm

<u>-TheUnknownScientist 72</u>

5 0
3 years ago
Read 2 more answers
An astronaut in her space suit has a total mass of 87.0kg including suit and oxygen tank. Her tether line loses its attachment t
Shtirlitz [24]

Answer:

Explanation:

a )

In space due to weightlessness both astronaut and her oxygen tank will float .

when she throws the tank away from spacecraft , she will have a velocity in opposite direction ie towards the spacecraft . This happens due to conservation of momentum . She creates a momentum away so that she can get a momentum towards the spaceship.

So

m₁ v₁ = m₂v₂

12 x 8 = ( 87 - 12 ) x v₂

v₂ = 1.28 m /s

Time allowed = 2 x 60

= 120 s

So maximum distance upto which she can remain away from spacecraft

= 120 x 1.28

= 153 m .

b )

The Newton's law which explains the theory behind it is "third law of motion"  . This law gives law of conservation of momentum .  

6 0
4 years ago
A 100.0-kg bakery sign hangs from two thin cables as shown.
harina [27]

Answer:

1. T₁ = 500 N

2. T₂ = 866 N

Explanation:

Please see attached photo for the diagram.

Thus, we can obtain obtained the value of T₁ and T₂ as follow:

1. Determination of T₁

Angle θ = 30

Hypothenus = 100 kg

Opposite = T₁ =?

Sine θ = Opposite /Hypothenus

Sine 30 = T₁ / 100

Cross multiply

T₁ = 100 × Sine 30

T₁ = 100 × 0.5

T₁ = 50 Kg

Multiply by 10 to express in Newton

T₁ = 50 × 10

T₁ = 500 N

2. Determination of T₂

Angle θ = 60

Hypothenus = 100 kg

Opposite = T₂ = ?

Sine θ = Opposite /Hypothenus

Sine 60 = T₂ / 100

Cross multiply

T₂ = 100 × Sine 60

T₂ = 100 × 0.8660

T₂ = 86.6 Kg

Multiply by 10 to express in Newton

T₂ = 86.6 × 10

T₂ = 866 N

5 0
3 years ago
A 2.5m long steel piano wire has a diameter of 0.5cm how great is the tention in the wire if it stretches by 0.45cm when tighten
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Answer:                 Their u go i found it their was about 3 pages i did not no what pages u had to do.

Explanation:

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7 0
3 years ago
A particle is leaving the Moon in a direction that is radially outward from both the Moon and Earth.
Misha Larkins [42]

Answer:

2780m/s

Explanation:

Essentially, Kinetic energy of the particle must equal the combined potential energies of earth and the moon when the object is on the moon's surface, meaning the full equation is

<h3>\frac{1}{2} mv^2=\frac{G(M_E)m}{r_E} +G\frac{M_mm}{r_m}\\</h3><h3 />

M_E=Mass of Earth=5.97*10^2^4

M_m=Mass of Moon=7.4*10^2^2kg

r_E=distance from earth's center to the moon's=3.84*10^8m

r_m=radius of moon=1.738*10^6m

After some algebra, the equation simplifies to

v=\sqrt{2G*(\frac{M_E}{r_E+r_m}+\frac{M_m}{r_m})}

Plugging in the values of G, which is 6.67*10^-^1^1 \frac{m^3}{kg*s^2}, should yield the proper answer of 2780m/s.

4 0
3 years ago
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