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3 years ago

An object is dropped at a height of 12 m from the ground. How fast is it moving just before it hits the ground?

Physics

1 answer:

sp2606 [1]3 years ago

6 0

The final speed of the object is 15.3 m/s

Explanation:

The object in the problem is moving by uniformly accelerated motion (it is in free fall), so we can use the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

$a=g=9.8 m/s^2$ is the acceleration of gravity (taking downward as positive direction)

s is the vertical displacement

For the object in this problem:

u = 0 (it starts from rest)

s = 12 m is the displacement of the object

Solving for v,

$v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(12)}=15.3 m/s$

Learn more about free fall motion here:

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$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

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