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Oxana [17]
3 years ago
13

An object is dropped at a height of 12 m from the ground. How fast is it moving just before it hits the ground?

Physics
1 answer:
sp2606 [1]3 years ago
6 0

The final speed of the object is 15.3 m/s

Explanation:

The object in the problem is moving by uniformly accelerated motion (it is in free fall), so we can use the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a=g=9.8 m/s^2 is the acceleration of gravity (taking downward as positive direction)

s is the vertical displacement

For the object in this problem:

u = 0 (it starts from rest)

s = 12 m is the displacement of the object

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(12)}=15.3 m/s

Learn more about free fall motion here:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

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Answer:

The correct option is (d). "3x stronger".

Explanation:

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Answer:

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From the question we are told that

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Generally the energy of the incident light is mathematically represented as

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Here c is the speed of light with value c =  3.0 *10^{8} \  m/s

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