Question

An object is dropped at a height of 12 m from the ground. How fast is it moving just before it hits the ground?

Answer 1

The final speed of the object is 15.3 m/s

Explanation:

The object in the problem is moving by uniformly accelerated motion (it is in free fall), so we can use the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

$a=g=9.8 m/s^2$ is the acceleration of gravity (taking downward as positive direction)

s is the vertical displacement

For the object in this problem:

u = 0 (it starts from rest)

s = 12 m is the displacement of the object

Solving for v,

$v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(12)}=15.3 m/s$

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