An object is dropped at a height of 12 m from the ground. How fast is it moving just before it hits the ground?
1 answer:
The final speed of the object is 15.3 m/s
Explanation:
The object in the problem is moving by uniformly accelerated motion (it is in free fall), so we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
is the acceleration of gravity (taking downward as positive direction)
s is the vertical displacement
For the object in this problem:
u = 0 (it starts from rest)
s = 12 m is the displacement of the object
Solving for v,
Learn more about free fall motion here:
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Answer:
Explanation:
We need the power equation here:
P = W/t where W is work and is defined as
W = F*displacement.
Force is a measure in Newtons, which is also weight. We have the mass of the piano, but we need to find the weight:
w = mg so
w = 166(9.8) so
w = 1600N, rounded to the correct number of sig dig. We use that now in the power equation:
and isolating the unknown:
so
t = 5.3 seconds