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3 years ago

Can someone help me please with this 100% correct only

Mathematics

1 answer:

DiKsa [7]3 years ago

6 0

The answer would be cone. Do you need reasoning?

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If Val walls 1/2 mile for every 3/4 mile she runs if she walked 2 miles how many miles did she run

Usimov [2.4K]

Answer: She ran 3 miles

Explanation:
1/2 miles walked) • X = (2 Miles walked)

X= 4

4 • 3/4 miles ran = 12/4 miles ran = 3 miles ran.

6 0

2 years ago

Type the correct answer in the box. Lily owed Megan $129.42. So far, she has paid Megan $32.56. The remaining amount Lily has ye

mario62 [17]

Answer:

$96.86

Step-by-step explanation:

129.42-32.56 = 96.86

Lily still has to pay $ 96.86

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3 years ago

Mary wants to apply a strip of wallpaper along the walls just below the ceiling. If the room is a 14 ft by 12 ft rectangle, then

Yuliya22 [10]

Answer:

Step-by-step explanation:

In this case, we need to calculate a perimeter, which is the sum of all sides of the rectangle.

So, rectangles has opposite sides equal, therefore, the perimeter should be:

$P=2 (L+l)$ ; having L as the larger side.

$P=2(14+12)\\P=2(26)\\P=52$

Hence, the strip of wallpaper needs to be as least 52 ft.

6 0

4 years ago

In a function if the vaule of a changes in response to the vaule of b then b is the

d1i1m1o1n [39]

<span>b is the independent variable ok</span>

5 0

3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

3 years ago