<span>The graph would be translated 5 units right and 1 unit up, giving an upward facing parabola with a vertex at (5, 1).
Explanation:
Since 5 was subtracted from x before it was squared, this means a horizontal translation 5 units. Since it was subtracted, this means it was translated right 5 units.
The 1 added at the end means it was translated 1 unit up as well.
This is in vertex form, y=a(x-h)^2 + k, where (h, k) is the vertex; h corresponds with 5 and k corresponds with 1, so the vertex is at (5, 1).</span>
Answer:
Slope = -
Y-intercept = 4
Step-by-step explanation:
-> See attached
-> This equation is in slope-intercept form.
[] When we use y = mx + b, the m is the slope and the b is our y-intercept.
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.
- Heather
Answer:
A(y=3) B(y = -2) C(y= 4)
A' (y = 3) B(y= -2) C(y= 4)
Step-by-step explanation:
I added the diagram of the question.
<u><em>Answer:</em></u>h = 60°
<u><em>Explanation:</em></u>We are given that lines k and l are parallel lines.
This means that angles 120° and h are <u>supplementary angles</u>.
This means that their measures <u>add up to 180°</u>
<u>Therefore:</u>
180° = 120° + h
h = 180° - 120°
h = 60°
Hope this helps :)
Answer:
C
Step-by-step explanation:
The center of inscribed circle into triangle is point of intersection of all interior angles of triangle.
The center of circumscribed circle over triabgle is point of intersection of perpendicular bisectors to the sides.
Circumscribed circle always passes through the vertices of the triangle.
Inscribed circle is always tangent to the triangle's sides.
In your case angles' bisectors and perpendicular bisectors intesect at one point, so point A is the center of inscribed circle and the center of corcumsribed circle. Thus, these circles pass through the points X, Y, Z and G, E, F, respectively.