Answer:
Volume of chlorine = 61.943 mL
Explanation:
Given:
Volume of the water in the Pool = 18,000 gal
also,
1 gal = 3785.412 mL
thus,
Volume of water in pool = 18,000 × 3785.412 = 68,137,470 mL
Density of water = 1.00 g/mL
Therefore,
The mass of water in the pool = Volume × Density
or
The mass of water in the pool = 68,137,470 mL × 1.00 g/mL = 68,137,470 g
in terms of million =
or
= 68.13747 g
also,
1 g of chlorine is present per million grams of water
thus,
chlorine present is 68.13747 g
Now,
volume =
or
Volume of chlorine =
or
Volume of chlorine = 61.943 mL
The answer is D. To put it simply, all atom wished to become stable. The only way for that is to obtain an octet structure where the outermost shell would have 8 electrons, thus being full.
The concentration of [CI-] : 0.617 M
<h3>Further explanation</h3>
FeCl₃ dissolved in 450 mL of solution(will dissociate )
Reaction
FeCl₃⇒Fe³⁺+3Cl⁻
- mol FeCl₃(MW=162,2 g/mol)
![\tt \dfrac{15}{162.2}=0.0925](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B15%7D%7B162.2%7D%3D0.0925)
![\tt \dfrac{3}{1}\times 0.0925=0.2775](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B3%7D%7B1%7D%5Ctimes%200.0925%3D0.2775)
![\tt \dfrac{0.2775}{0.45}=0.617~M](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B0.2775%7D%7B0.45%7D%3D0.617~M)
CO2 + H2O + Energy are the comments
your answer is b hope this helps