Given k=100, Area if plate A = 1.00 cm2
Thickness of rutile 
Without any dielectric medium capacitance of a parallel plate capacitor is c = oAd
When a dielectric is placed between capacitors plates then capacitance c1 = KoAd
Here 
, 
Now 
Correct Option: A
What purposes serve parallel plate capacitors?
The following are some uses for parallel plate capacitors:
- This kind of capacitor is utilized in rechargeable energy systems such as batteries.
- These capacitors are used in systems for dynamic digital memory.
- Such capacitors are used in pulsed laser and radar circuits.
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Answer:
a 
b 
Explanation:
Generally the force constant is mathematically represented as
substituting values given in the question
=> 
=> 
Generally the workdone in stretching the spring 3.5 m is mathematically represented as
=> 
=>
Generally the workdone in compressing the spring 2.5 m is mathematically represented as
=> 
=>
Answer:
has free electrons
Explanation:
A conductor has free electrons while an insulator does not. Free electrons are electrons which are not bounded tightly to their parent atoms, and are free to move given the right conditions (ie. a strong EM field).
Answer:
(a) Total north component = (26.89 + 25) = 51.89 metres
(b) Total west component = (-34.83 + 52) = 17.17 metres.
Explanation:
Do northwest components first.
North component = (sin 33.9 x 44) =26.89 metres.
West component = (cos 33.9 x 44) = -34.83metres.
Total west component = (-34.83 + 52) = 17.17 metres.
Total north component = (26.89 + 25) = 51.89 metres
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