What is the electric force on a proton 2.5 fm from the surface of the nucleus? hint: treat the spherical nucleus as a point char
1 answer:
In this case, you need the formula below where:
F = force
k = coulombs constant 8.99 x10^{9} N.m^{2} . C^{-2}
q1 = electric charge 1
q2 = electric charge 2
r = the distance between the charges
pls note: make sure your units are correct (in meters etc, not fm (<em>femto-meters</em>)).
Curiously, this question doesn't tell you what atom you are next to the nucleus of. Different numbers of protons in the nucleus of the atom will make for vastly different forces in your answer...
F = force
k = coulombs constant 8.99 x10^{9} N.m^{2} . C^{-2}
q1 = electric charge 1
q2 = electric charge 2
r = the distance between the charges
pls note: make sure your units are correct (in meters etc, not fm (<em>femto-meters</em>)).
Curiously, this question doesn't tell you what atom you are next to the nucleus of. Different numbers of protons in the nucleus of the atom will make for vastly different forces in your answer...
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The image height is -10 cm (the image is upside down)
Explanation:
We can solve the problem by using the mirror equation:
where:
f = 5 cm is the focal length of the mirror
p = 10 cm is the distance of the object from the mirror
q is the distance of the image from the mirror
Solving for q, we find:
So, the distance of the image from the mirror is 10 cm.
Now we can find the image height by using the magnification equation:
where
y' is the height of the image
y = 1 cm is the height of the object
and using
p = 10 cm
q = 10 cm
We find the size of the image:
where the negative sign indicates that the image is upside down.
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