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Novay_Z [31]
3 years ago
9

Name a force that opposes the movement of an object through water.

Physics
1 answer:
VikaD [51]3 years ago
4 0
That is frictional force
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Two concentric conducting spherical shells produce a radially outward electric field of magnitude49,000 N/C at a point 4.10 m fr
Korolek [52]

To solve this problem it is necessary to apply the concepts related to the electric field according to the definition of Coulomb's law.

 The electric field is defined mathematically as a vector field that associates to each point in space the (electrostatic or Coulomb) force per unit of charge exerted on an infinitesimal positive test charge at rest at that point.

Mathematically this can be described as:

E = \frac{1}{4\pi \epsilon_0}\frac{q}{r^2}

Where,

\epsilon_0 = permittivity of free space

r = Distance

q = Charge

E = Electric Field

Our values are given as,

E= 49.000N/C

r= 4.1m

\epsilon_0=8.854*10{-12}C^2N^{-1}m^{-2}

Replacing we have,

E = \frac{1}{4\pi \epsilon_0}\frac{q}{r^2}

49000 = \frac{1}{4\pi (8.854*10{-12})}\frac{q}{(4.1)^2}

q= 9.16*10^{-5} C

q= 91.6\mu C

Therefore the amoun of charge on the outer surface of the larger shell is 91.6 \mu C

6 0
4 years ago
El peso de María es de 617,4 N. Si en dos meses pierde 2,5 Kg de masa, ¿cuál será su nuevo peso?
NeTakaya
Two hundred and thirsty years
5 0
4 years ago
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I have to write an essay about Quantum Mechanics. I need to know everything about it. Please Help!
Studentka2010 [4]

ananı var ya ananı

kodumun abd lisi aptal cajhil özürlü

6 0
3 years ago
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A 1.25 kg block is attached to a spring with spring constant 17.0 N/m . While the block is sitting at rest, a student hits it wi
Free_Kalibri [48]

Answer:

The amplitude of the subsequent oscillations is 13.3 cm

Explanation:

Given;

mass of the block, m = 1.25 kg

spring constant, k = 17 N/m

speed of the block, v = 49 cm/s = 0.49 m/s

To determine the amplitude of the oscillation.

Apply the principle of conservation of energy;

maximum kinetic energy of the stone when hit = maximum potential energy of spring when displaced

K.E_{max} = U_{max}\\\\\frac{1}{2} mv^2 = \frac{1}{2} kA^2\\\\where;\\\\A \ is \ the \ maximum \ displacement = amplitude \\\\mv^2 = kA^2\\\\A^2 = \frac{mv^2}{k} \\\\A = \sqrt{\frac{mv^2}{k}} \\\\A =  \sqrt{\frac{1.25\  \times \ 0.49^2}{17}} \\\\A = 0.133 \ m\\\\A = 13.3 \ cm

Therefore, the amplitude of the subsequent oscillations is 13.3 cm

6 0
3 years ago
How can we avoid water pollution​
Alexandra [31]

Explanation:

1.Pick up litter and throw it away in a garbage can.

2.Blow or sweep fertilizer back onto the grass if it gets onto paved areas. ...

3.Mulch or compost grass or yard waste. ...

4.Wash your car or outdoor equipment where it can flow to a gravel or grassed area instead of a street.

5.Don't pour your motor oil down the storm drain.

8 0
3 years ago
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