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Sergeeva-Olga [200]
3 years ago
5

CHEM PLZ HELP, Which thermochemical equation represents the most exothermic reaction?

Chemistry
1 answer:
uysha [10]3 years ago
3 0

Answer:

The answer is option 3, C5H12 + 8O2 → 5CO2 + 6H2O.

Explanation:

In an exothermic reaction, the energy change(ΔH) will always be a negative value.

For endothermic reaction, the energy change's value is positive.

In the options above, option 1 and 2 are endothermic reaction.

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PLEASE HELP!!! Just need an answer, no explanation
Alex

Answer: N2

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6 0
3 years ago
Read 2 more answers
Give three properties of a Solid
NARA [144]
In a solid, molecules are packed together, and it keeps its shape. Liquids take the shape of the container. Gases spread out to fill the container. Solid is one of the three main states of matter, along with liquid and gas.

Hope that helps!
8 0
3 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

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5 0
2 years ago
وزن الملي مكافئ لحامض الخليك​
Natalka [10]

Answer:

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Explanation:

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3 0
3 years ago
The reaction of Pb+4 and O-2 produces the compound of
vovikov84 [41]

Answer:

Pb₂O₄

                               

Explanation:

The given species are:

        Pb⁴⁺               O²⁻  

Now, to solve this problem, we use the combining powers which corresponds to the number of electrons usually lost or gained or shared by atoms during the course of a chemical combination.

                                          Pb⁴⁺               O²⁻  

Combining power               4                    2

Exchange of valencies        2                    4

Now the molecular formula is  Pb₂O₄

                               

4 0
2 years ago
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