Question

In order to get lots of helium into tanks to fill kiddy balloons, they put force or pressure onto it. If i have 595 liters of helium at 1.00 atmosphere of pressure (that’s normal air pressure, or the pressure of the air), then what volume would it have if i applied 55.0 atmospheres of force or pressure to it?

Answer 1

Answer:

1.90 L

Explanation:

Using Boyle's law  

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,  

V₁ = 595 L  

V₂ = ?

P₁ = 1.00 atm

P₂ = 55.0 atm

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${1.00}\times {595}={55.0}\times {V_2}$

${V_2}=\frac{{1.00}\times {595}}{55.0}\ L$

${V_2}=1.90\ L$

The volume would be 1.90 L.