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alexira [117]
3 years ago
10

Formula One race cars are capable of remarkable accelerations when speeding up, slowing down, and turning corners. At one track,

cars round a corner that is a segment of a circle of radius 95 m at a speed of 68 m/s. What is the approximate magnitude of the centripetal acceleration, in units of g?
Physics
1 answer:
anygoal [31]3 years ago
3 0

Answer:

Centripetal acceleration of the car is (4.96 g) m/s²

Explanation:

It is given that,

Radius of circle, r = 95 m

Speed of the car, v = 68 m/s

We need to find the centripetal acceleration. It is given by :

a_c=\dfrac{v^2}{r}

So, a_c=\dfrac{(68\ m/s)^2}{95\ m}

a_c=48.67\ m/s^2

Since, g = 9.8 m/s²

So,

a_c=(4.96\ g)\ m/s^2

So, the magnitude of the centripetal acceleration is (4.96 g) m/s². Hence, this is the required solution.

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Which of the following observations represent conclusive evidence of an interaction? (Select all that apply.)
9966 [12]

Answer:

a,b,d and e are correct.

Explanation:

a) Change of temperature without change of velocity is a conclusive evidence of an interaction. As the temperature of a body will only change if heat energy is flows in or out of the body with surrounding. So, option a) is correct.

b) Change of the direction without change of speed is an evidence of an interaction. The direction changes when the object is under a perpendicular acceleration acceleration which clearly means the particle is interacting or external force applied. So, option b is correct.

d) Change of shape or configuration without change of velocity is conclusive evidence of an interaction. The shape can change only if external stress is applied on the particle. So, Option d is correct.

e) Change of identity without change of velocity is a conclusive evidence of an interaction. The identity of an object can only change if it interacts with surroundings. So, option e is correct

Therefore the only incorrect option is c .

6 0
3 years ago
The magnetic field at the center of a 1.40-cm-diameter loop is 2.50 mT . PART A) What is the current in the loop?
NISA [10]

Explanation:

It is given that,

Diameter of loop, d = 1.4 cm

Radius of loop, r = 0.7 cm = 0.007 m

Magnetic field, B=2.5\ mT=2.5\times 10^{-3}\ T

(A) Magnetic field of a current loop is given by :

B=\dfrac{\mu_oI}{2r}

I is the current in the loop

I=\dfrac{2Br}{\mu_o}

I=\dfrac{2\times 2.5\times 10^{-3}\times 0.007}{4\pi \times 10^{-7}}

I = 27.85 A

(B) Magnetic field at a distance r from a wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

r=\dfrac{\mu_o I}{2\pi B}

r=\dfrac{4\pi \times 10^{-7}\times 27.85}{2\pi \times 2.5\times 10^{-3}}

r = 0.00222 m

r=2.2\times 10^{-3}\ m

Hence, this is the required solution.

3 0
3 years ago
The length of the side of a cube is 10.0 ±0.3 cm. What is the absolute uncertainty in the perimeter of one side of the cube?
Nimfa-mama [501]

Answer:Stuff

Explanation: Nun

4 0
3 years ago
A 12-volt automotive circuit has a current of 3 amps. Technician A says the electric power in this circuit is 36 watts. Technici
skelet666 [1.2K]

Answer:

Technician A is right.                                                    

Explanation:

Given that,

Voltage of circuit, V = 12 volt

Current in the circuit, I = 3 A

Technician A says the electric power in this circuit is 36 watts. Technician B says the electric power in this circuit is 4 watts. We need to say that which technician is correct.

The power of any circuit is given by :

P=V\times I

P=12\ V\times 3\ A

P = 36 watts

So, technician A is right. Hence, this is the required solution.

6 0
2 years ago
At 5.0 minutes, the temperature of the water reaches 100 °C. The volume of the water in the urn
serious [3.7K]

Answer:

fdvevddvevkejokef0jeovdlvkjeuiyv

Explanation:

ddf4edscd

4 0
3 years ago
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