The frequency of the wave is 6800 Hz
<u>Explanation:</u>
Given:
Wave number, n = 20
Speed of light, v = 340 m/s
Frequency, f = ?
we know:
wave number = 

Therefore, the frequency of the wave is 6800 Hz
I would think that you would multiply then divide
A.
since they do not have a definite volume, this causes it to spread out in the air
The distance from a 27 mw point source of electromagnetic waves where the electric field amplitude 0. 060 v/m will be 21.21 m .
Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields.
The highest point of a wave is known as 'crest' , whereas the lowest point is known as 'trough'. Electromagnetic waves can be split into a range of frequencies. This is known as the electromagnetic spectrum.
c = 3 *
m/s
∈ = 8.85 *
/ N/ 
E = 0. 060 v/m
I = P / 4π
Also , I = c ∈
/2
= P / 4π I equation 1
substituting the value of I in equation 1
= 2 P / 4π (c ∈
)
= 2 * 27 *
/ 4 * 3.14 * 3 *
* 8.85 *
* 
r = 21.21 m
To learn more about Electromagnetic waves here
brainly.com/question/12392559
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Gamma Rays Hope This Helps