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vitfil [10]
3 years ago
7

I am so confused please help

Physics
1 answer:
dexar [7]3 years ago
3 0
The Answer is B as it is the only reasonable answer that favors Nuclear Energy.
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If you exert 250J of work onto a lever that is 5m long, what amount of force are you applying?
maks197457 [2]
From the formula of W = F·d , becuase we have the values for W and d we can find F

W = F·d 
F= W/d
  = 250/5
  = 50 N

40 N of force was applied
7 0
3 years ago
Read 2 more answers
Q.1 Newton's second law gives the measure of--------------. 1)Acceleration 2) Force 3) Momentum 4)Angular momentum​
posledela

Answer:

1. Acceleration

Explanation:

Newtons Second law gives the measure of acceleration

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3 years ago
How can you increase the intensity of sound waves
VladimirAG [237]

Answer

The intensity of a sound wave depends on the pressure of the wave,density of the medium and speed of sound in the medium. Higher density and higher sound speed both give a lower intensity. and may be it is because that sound wave is more characterize by wavelength than frequency..explanation

Explanation:

As decibel levels get higher, sound waves have greater intensity and sounds are louder. For every 10-decibel increase in the intensity of sound, loudness is 10 times greater. Intensity of sound results from two factors: the amplitude of the sound waves and how far they have traveled from the source of the sound.

5 0
2 years ago
The blades in a blender rotate at a rate of 6100 rpm. When the motor is turned off during operation, the blades slow to rest in
MissTica

Answer:

<em>155.80rad/s</em>

Explanation:

Using the equation of motion to find the angular acceleration:

\omega_f = \omega_i + \alpha t

\omega_f is the final angular velocity in rad/s

\omega_i  is the initial angular velocity in rad/s

\alpha is the angular acceleration

t is the time taken

Given the following

\omega_f = 6100rpm

Time = 4.1secs

Convert the angular velocity to rad/s

1rpm = 0.10472rad/s

6100rpm = x

x = 6100 * 0.10472

x  = 638.792rad/s

\omega_f = 638.792rad/s\\

Get the angular acceleration:

Recall that:

\omega_f = \omega_i + \alpha t

638.792 = 0 + ∝(4.1)

4.1∝ = 638.792

∝ = 638.792/4.1

∝ = 155.80rad/s

<em>Hence the angular acceleration as the blades slow down is 155.80rad/s</em>

5 0
2 years ago
an object tied to the end of the string moves in a circle . the force exerted by the string depends on the mass of the object it
otez555 [7]

Answer:Fc=mv^2/r

Explanation:

6 0
3 years ago
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