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vitfil [10]
4 years ago
7

I am so confused please help

Physics
1 answer:
dexar [7]4 years ago
3 0
The Answer is B as it is the only reasonable answer that favors Nuclear Energy.
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What elements are formed only during the supernova phase of large or extra-large madd star?
Fed [463]
Elements heavier than iron are formed in a supernova, the heavier elements up to uranium appear when a star with needed mass collapses in a supernova event some times referred too trans-iron elements.
7 0
3 years ago
Is chocolate melting in your hand conduction, convection, or radiation?
VikaD [51]

Answer:

Conduction

Explanation:

"Conduction is the process by which heat energy is transmitted through collisions between neighboring atoms or molecules."

The heat in your hand melts that chocolate, making it conduction.

7 0
3 years ago
Read 2 more answers
What height will the object reach? 12 points. Will give brainliest.
umka21 [38]

Answer:

12.7 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 56.7 Km/hr

Maximum height (h) =..?

First, we shall convert 56.7 Km/hr to m/s. This can be obtained as follow:

Initial velocity (m/s) = 56.7 x 1000/3600

Initial velocity (m/s) = 15.75 m/s

Next, we shall determine the time taken to get to the maximum height. This can be obtained as follow:

Initial velocity (u) = 15.75 m/s

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

v = u – gt (since the ball is going against gravity)

0 = 15.75 – 9.8 × t

Rearrange

9.8 × t = 15.75

Divide both side by 9.8

t = 15.75/9.8

t = 1.61 secs.

Finally, we shall determine the maximum height as follow

h = ½gt²

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 1.61 secs.

Height (h) =..?

h = ½gt²

h = ½ × 9.8 × 1.61²

h = 4.9 x 1.61²

h = 12.7 m

Therefore, the maximum height reached by the ball is 12.7 m

3 0
3 years ago
In part one of this experiment, a 0.20 kg mass hangs vertically from a spring and an elongation below the support point of the s
statuscvo [17]

To solve this problem it is necessary to apply the concepts related to Hooke's Law as well as Newton's second law.

By definition we know that Newton's second law is defined as

F = ma

m = mass

a = Acceleration

By Hooke's law force is described as

F = k\Delta x

Here,

k = Gravitational constant

x = Displacement

To develop this problem it is necessary to consider the two cases that give us concerning the elongation of the body.

The force to keep in balance must be preserved, so the force by the weight stipulated in Newton's second law and the force by Hooke's elongation are equal, so

k\Delta x = mg

So for state 1 we have that with 0.2kg there is an elongation of 9.5cm

k (9.5-l)=0.2*g

k (9.5-l)=0.2*9.8

For state 2 we have that with 1Kg there is an elongation of 12cm

k (12-l)= 1*g

k (12-l)= 1*9.8

We have two equations with two unknowns therefore solving for both,

k = 3.136N/cm

l = 8.877cm

In this way converting the units,

k = 3.136N/cm(\frac{100cm}{1m})

k = 313.6N/m

Therefore the spring constant is 313.6N/m

3 0
3 years ago
A wrench is placed at 30 cm in front of a diverging lens with a focal length of magnitude 10 cm. What is the magnification of th
WARRIOR [948]

Answer:

0.25

Explanation:

Magnification = image distance/object distance

mag = v/u.................. Equation 1

Given: f = -10 cm ( diverging lens) u = 30 cm.

Where can calculate for the value of v using

1/f = 1/u+1/v

make v the subject of the equation

v = fv/(u-f)..................... Equation 2

Substitute into equation 2

v = -30(10)/(30+10)

v = -300/40

v = -7.5 cm.

substituting into equation 1,

mag = 7.5/30

mag = 0.25

hence the magnification of the wretch = 0.25

4 0
3 years ago
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