Answer:
A) False
B) False
C) True
D) False
Explanation:
A) False, because when leaving the field, the coil experiences a magnetic force to the right.
B) When the loop is entering the field, the magnetic flux through it will increase. Thus, induced magnetic field will try to decrease the magnetic flux i.e. the induced magnetic field will be opposite to the applied magnetic field. The applied magnetic field is into the plane of figure and thus the induced magnetic field is out of the plane of figure. Due to that reason, the current would be counterclockwise. So the statement is false.
C) When the loop is leaving the field, the magnetic flux through the loop will decrease. Thus, induced magnetic field will try to increase the magnetic flux i.e. the inducued magnetic field will be in the same direction as the applied magnetic field. The applied magnetic field is into the plane of figure and thus the induced magnetic field is also into the plane of figure. Due to that reason, the current would be clockwise. So the statement is true.
D) False because when entering the field magnetic force will be toward left side
Answer:
0.00098 N
Explanation:
The weight of an object is given by:

where
m is the mass of the object
g is the gravitational acceleration on the planet
In this problem, we have:
is the mass of the honeybee
is the acceleration due to gravity
Substituting into the equation, we find:

Answer:
Star, hydrogen and energy
Explanation:
A star is a large ball of gas that generates its own energy by fusing hydrogen atoms to make helium. It is held together by its own gravity. This process emits a tremendous amount of energy, and some of the energy is in the form of light.
The energy released from the collapse of the gas into a protostar causes the center of the protostar to become extremely hot. When the core is hot enough, nuclear fusion commences. Fusion is the process where two hydrogen atoms combine to form a helium atom, releasing energy.
To develop the problem we will start by finding the energy taken by each cycle through the efficiency of the motor and the exhausted energy. Later the work will be found for the conservation of energy in which this is equivalent to the difference between the two calculated energy values. Finally the estimated time will be calculated with the work and the power given,








PART A)
Work done by the heat engine in each cycle = W



According to the value given we have that,


Power is defined as the variation of energy as a function of time therefore,




Therefore the interval for each cycle is 0.75s