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quester [9]
3 years ago
6

What effect does El Nino have on Michigan's winters such as this winter (2017)?

Physics
1 answer:
lianna [129]3 years ago
6 0
The best and most correct answer among the choices provided by the question is the second choice. The effect of El Nino was that it gave extremely cold weather in Michigan. I hope my answer has come to your help. God bless and have a nice day ahead!
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According to Newton's first law of motion, what would happen to a car traveling at a constant velocity of 55 MPH to the west in
mart [117]

Explanation:

  • Newton's first law of motion says that an object will be at rest or it will be in motion until an unbalanced force acts on it.
  • In this case, a car traveling at a constant velocity of 55 mph to the west in the absence of an unbalanced force.
  • It would mean that the car will continue to move with a constant velocity of 55 mph to the west due to Newton's first law of motion.
6 0
2 years ago
A square loop of wire with a small resistance is moved with constant speed from a field free region into a region of uniform B f
Misha Larkins [42]

Answer:

A) False

B) False

C) True

D) False

Explanation:

A) False, because when leaving the field, the coil experiences a magnetic force to the right.

B) When the loop is entering the field, the magnetic flux through it will increase. Thus, induced magnetic field will try to decrease the magnetic flux i.e. the induced magnetic field will be opposite to the applied magnetic field. The applied magnetic field is into the plane of figure and thus the induced magnetic field is out of the plane of figure. Due to that reason, the current would be counterclockwise. So the statement is false.

C) When the loop is leaving the field, the magnetic flux through the loop will decrease. Thus, induced magnetic field will try to increase the magnetic flux i.e. the inducued magnetic field will be in the same direction as the applied magnetic field. The applied magnetic field is into the plane of figure and thus the induced magnetic field is also into the plane of figure. Due to that reason, the current would be clockwise. So the statement is true.

D) False because when entering the field magnetic force will be toward left side

8 0
3 years ago
The acceleration due to gravity on Earth is 9.80 m/s2. If the mass of a honeybee is 0.000100 kilograms, what is the weight of th
Yuliya22 [10]

Answer:

0.00098 N

Explanation:

The weight of an object is given by:

W=mg

where

m is the mass of the object

g is the gravitational acceleration on the planet

In this problem, we have:

m=0.0001 kg is the mass of the honeybee

g=9.8 m/s^2 is the acceleration due to gravity

Substituting into the equation, we find:

W=mg=(0.0001 kg)(9.8 m/s^2)=0.00098 N

4 0
3 years ago
Read 2 more answers
A ___ is a large ball of gas that generates its own energy. This energy is created by the fusion of ___ atoms to make ___.
Murljashka [212]

Answer:

Star, hydrogen and energy

Explanation:

A star is a large ball of gas that generates its own energy by fusing hydrogen atoms to make helium. It is held together by its own gravity. This process emits a tremendous amount of energy, and some of the energy is in the form of light.

The energy released from the collapse of the gas into a protostar causes the center of the protostar to become extremely hot. When the core is hot enough, nuclear fusion commences. Fusion is the process where two hydrogen atoms combine to form a helium atom, releasing energy.

8 0
2 years ago
A particular heat engine has a mechanical power output of 4.00 kW and an efficiency of 26.0%. The engine expels 8.55 103 J of ex
Ivahew [28]

To develop the problem we will start by finding the energy taken by each cycle through the efficiency of the motor and the exhausted energy. Later the work will be found for the conservation of energy in which this is equivalent to the difference between the two calculated energy values. Finally the estimated time will be calculated with the work and the power given,

\text{Efficiency of the heat engine} = \eta = 26\% = 0.26

\text{Energy taken in by the heat engine during each cycle} = Q_h

\text{Energy exhausted by the heat engine in each cycle} = Q_c = 8.55*10^3 J

\eta = 1 - \frac{Q_{c}}{Q_{h}}

0.26 = 1 - \frac{8.55\ast 10^{3}}{Q_{h}}

\frac{8.55* 10^{3}}{Q_{h}} = 0.74

Q_h = \frac{8.55*10^3}{0.74}

Q_h = 11.554*10^3J

PART A)

Work done by the heat engine in each cycle = W

W = Q_h-Q_c

W = 11.554*10^3J-8.55*10^3J

W = 3004J

According to the value given we have that,

P = 4.0kW

P = 4000W

Power is defined as the variation of energy as a function of time therefore,

P = \frac{W}{t}

4000W = \frac{3004J}{t}

t = \frac{3004}{4000}

t = 0.75s

Therefore the interval for each cycle is 0.75s

5 0
3 years ago
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