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1 year ago

Please help me with this rotation and linear motion problem

Physics

1 answer:

kirill115 [55]1 year ago

5 0

The initial angular velocity of the wheel would be 15.5 rad/s

<h3>What is Velocity?</h3>

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second.

The relation between the linear velocity and the angular velocity

V= ωr

as given the initial linear velocity is 8.22 m/s

the radius of the wheel is 0.530 m

By substituting the value of the linear velocity and the radius

8.22 = 0.530ω

ω = 8.22/0.530

ω = 15.5 rad/s

Thus, the initial angular velocity of the wheel comes out to be 15.5 rad/s

Learn more about Velocity from here

brainly.com/question/18084516

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2 years ago

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1 year ago

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3 years ago

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A piece of wood has a volume of 4.6 cm to the power of 3, and a mass of 3.7 g what is the density of the wood

AysviL [449]

Density is given by:

D = M/V

D = density, M = mass, V = volume

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3 0

3 years ago

A glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.90 x 105 P

worty [1.4K]

Answer:

The magnitude of the force is 34.59 N.

Explanation:

Given that,

Inside pressure $P_{in}= 1.90\times10^{5}\ Pa$

Area $A=3.90\times10^{-4}\ m^2$

Outside pressure = 1 atm

We need to calculate the magnitude of the force

Using formula of force

$F_{net}=F_{in}-F_{out}$

$F_{net}=(P_{in}-P_{out})A$

Where, $P_{in}$ =inside Pressure

$P_{out}$ =outside Pressure

A = area

Put the value into the formula

$F_{net}=(1.90\times10^{5}-1.013\times10^{5})3.90\times10^{-4}$

$F_{net}=34.59\ N$

Hence, The magnitude of the force is 34.59 N.

6 0

3 years ago