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3 years ago

Which statement best compares the accelerations of two objects in free fall?

2 answers:

3 0

Answer: option D). The objects have the same acceleration.

The acceleration of both objects is g (acceleration of gravity).

In freefall the only force acting is the attraction of the earth (gravity). There is not air resistance.The acceleration is not dependent either of the mass or the surface area of the object.

Dennis_Churaev [7]3 years ago

3 0

The answer is: D) The objects have the same acceleration.

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If we start with 1.000 g of cobalt-60, 0.675 g will remain after 3.00 yr. this means that the of is _____

Tju [1.3M]

<span>Cobalt-60 is undergoing a radioactivity decay.

The formula of the decay is n=N(1/2)</span>∧(T/t).
<span>Where N </span>⇒ original mass of cobalt
<span> n </span>⇒ remaining mass of cobalt after 3 years
T ⇒ decaying period
t ⇒ half-life of cobalt.

So,
0.675 = 1 × 0.5∧(3/t)
log 0.675 = log 0.5∧(3/t)
3/t = log 0.675 ÷log 0.5
3/t= 0.567

t = 3÷0.567
= 5.290626524

the half-life of Cobalt-60 is 5.29 years.

<span>
</span><span>
</span>

8 0

2 years ago

An object propelled upwards with an acceleration of 2.0 m / s ^ 2 is launched from rest. After 6 seconds the fuel runs out. Dete

dezoksy [38]

Answer:43.34 m

Explanation:

Given

acceleration(a) $=2 m/s^2$

Initial Velocity(u)=0 m/s

After 6 s fuel runs out

Velocity after 6 s

v=u+at

$v=0+2\times 6=12 m/s$

After this object will start moving under gravity

height reached in first 6 s

$s=ut+\frac{at^2}{2}$

$s=0+\frac{2\times 6^2}{2}$

s=36 m

After fuel run out distance traveled in upward direction is

$v^2-u^2=2as_0$

here v=0

u=12 m/s

$a=9.8 m/s^2$

$0-12^2=2(-9.8)(s)$

$s_0=\frac{144}{2\times 9.8}=7.34 m$

$s+s_0=36+7.34=43.34 m$

7 0

3 years ago

What's the time constant of a 10 H inductor and a 200 ohm resistor connected in series

melamori03 [73]

<h3>Option B</h3><h3>The time constant of a 10 H inductor and a 200 ohm resistor connected in series is 50 millisecond</h3>

<em><u>Solution:</u></em>

Given that,

10 H inductor and a 200 ohm resistor connected in series

To find: time constant

<em><u>The time constant in seconds is given as:</u></em>

$Time\ constant = \frac{L}{R}$

Where,

L is the inductance in henry and R is the resistance in ohms

$Time\ constant = \frac{10}{200}\\\\Time\ constant = 0.05\ seconds$

Convert to millisecond

1 second = 1000 millisecond

0.05 second = 0.05 x 1000 = 50 millisecond

Thus time constant is 50 millisecond

7 0

3 years ago

True or False? Mechanical waves do NOT need a medium to travel through.

stellarik [79]

Answer:

False.

Explanation:

Mechanical waves require a medium in order to transport their energy from one location to another.

6 0

3 years ago

Read 2 more answers

A 60 kg student in a rowboat on a still lake decides to dive off the back of the boat. The studen'ts horizontal aceleration is 2

TiliK225 [7]

As per the third law of Newton, the force exerted by the boat over the student is equal in magnitude to the force that the student exerted on the boat.

So, calculate the force on the student using the second law of Newton, Force = mass * acceleration.

Force on the student = 60 kg * 2.0 m/s^2 = 120 N.

=> horizontal force exerted by the student on the boat = 120 N

Answer: option d. 120 N. toward the back of the boat.

Of course it is toward the back because that is where the student jumped from..

4 0

3 years ago