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MrRa [10]
3 years ago
13

A pendulum consisting of a sphere suspended from a light string is oscillating with a small angle with respect to the vertical.

The sphere is then replaced with a new sphere of the same size but greater density and is set into oscillation with the same angle. How do the period, maximum kinetic energy, and maximum acceleration of the new pendulum compare to those of the original pendulum
Physics
1 answer:
anyanavicka [17]3 years ago
4 0

Answer:

Period remains the same, Max KE increases, Max acceleration is the same

Explanation:

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A nonzero net force acts on a particle and does work. Which one of the following statements is true?
arlik [135]

Answer:

option (D) is correct.

Explanation:

According to the work energy theorem, the work done by all forces is equal to the change in kinetic energy of the body.

the kinetic energy of a body is directly proportional to the square of the speed of the body.

As the kinetic energy change, the speed of the body also change.

Option (D) is correct.

5 0
3 years ago
A black hole is a ________
masya89 [10]

Answer:

Answer to the question:

Explanation:

A black hole is a finite region of space within which there is a mass concentration high and dense enough to generate a gravitational field such that no material particle, not even light, can escape it.

8 0
3 years ago
Which of the following about Dalton's theory of matter is true?
Lemur [1.5K]
D.Atoms can be divided into smaller parts.


Dalton's atomic theory was the first complete attempt to describe allmatter in terms of atoms and their properties. Dalton based his theory on the law of conservation of mass and the law of constant composition. The first part of his theory states that allmatter is made of atoms, which are indivisible.
6 0
3 years ago
If the amount of work done on a book was 10 J and the force required to move the book was 2.5 N, what was the distance the book
olga55 [171]

Answer:

Explanation:4meters

Work=10J

Force=2.5N

Distance=work ➗ force

Distance=10 ➗ 2.5

Distance=4meter

5 0
3 years ago
A water pipe is inclined 40.0° below the horizontal. The radius of the pipe at the upper end is 2.00 cm. If the gauge pressure a
aliya0001 [1]

Answer:

P_2 = -1.9 \times 10^8 Pa

Explanation:

As it is given that flow rate in the pipe is 20 cm^3/s

so we have

Q = A_1v_1 = A_2v_2

at the upper end the area is given as

A_1 = \pi r_1^2

A_1 = \pi(0.02)^2 = 1.26 \times 10^{-3} cm^2

Also at the other end

A_2 = \pi r_2^2

A_2 = \pi(0.01)^2 = 0.314 \times 10^{-3} cm^2

now the speed at two ends is given as

v_1 = \frac{20}{1.26 \times 10^{-3}}

v_1 = 159.15 m/s

v_2 = \frac{20}{0.314 \times 10^{-3}}

v_2 = 637 m/s

now by Bernoulli's theorem we have

P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2

now we have

0.112(1.013 \times 10^5) + \frac{1}{2}1000(159.15)^2 + 1000(9.81)(2.65sin40) = P_2 + \frac{1}{2}(1000)(637)^2 + 0

Now we have

P_2 = -1.9 \times 10^8 Pa

4 0
3 years ago
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