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SpyIntel [72]
4 years ago
13

Calculate the electric field strength required to just support an oil drop of mass

Physics
1 answer:
Ray Of Light [21]4 years ago
3 0

Answer:

E= 3.06 \times 10^{-17} N/C

Explanation:

As we know that the oil drop experiment tells us the balancing the gravitational force by electrostatic force.

So ,

Electrostatic force = Gravitational force

qE=mg

Here , q is charge , E is electric field , m is mass and g is gravity.

so,

E=\frac{mg}{q}

Insert values from question,

E=\frac{10^{-2}kg \times 9.8 m/s^{2}}{3.2 \times 10^{-19}C}

or

E= 3.06 \times 10^{-17} N/C

This is the required value of electric field.

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