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3 years ago

A car starts from rest it grains acceleration

Physics

1 answer:

Sunny_sXe [5.5K]3 years ago

7 0

Explanation:

Given,

A car is starting from rest, so it's initial velocity (u)= 0m/s

Acceleration (a) = 20m/s²

distance covered (s) = 50m

Therefore, time taken (t) = ?

Here,

s= ut + 1/2 at²

or, 50 = 0 × t + 1/2 × 20 × t²

or, 50 = 0 + 20t² /2

or, 50× 2= 20t²

or, 100 = 20t²

or, 100/20 = t²

or, 5 = t²

or, √5 = t

therefore, t = 2.2360 seconds.

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Answer:

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3 years ago

A pair of fuzzy dice is hanging by a string from your rearview mirror. while you are accelerating from a stoplight to 28 m/s in

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We can use the formula of motion in physics (2nd law od newton) in this problem:
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Applying acceleration formula:
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3 years ago

A ball is thrown upward with a speed of 28.2 m/s.A. What is its maximum height?B. How long is the ball in the air?C. When does t

Ede4ka [16]

Answer:

(A) The maximum height of the ball is 40.57 m

(B) Time spent by the ball on air is 5.76 s

Explanation:

Given;

initial velocity of the ball, u = 28.2 m/s

(A) The maximum height

At maximum height, the final velocity, v = 0

v² = u² -2gh

u² = 2gh

$h = \frac{u^2}{2g}\\\\h = \frac{(28.2)^2}{2*9.8}\\\\h = 40.57 \ m$

(B) Time spent by the ball on air

Time of flight = Time to reach maximum height + time to hit ground.

Time to reach maximum height = time to hit ground.

Time to reach maximum height is given by;

v = u - gt

u = gt

$t = \frac{u}{g}$

Time of flight, T = 2t

$T = \frac{2u}{g}\\\\ T = \frac{2*28.2}{9.8}\\\\ T = 5.76 \ s$

As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.

v² = u² - 2gh

12² = 28.2² - 2(9.8)h

12² - 28.2² = - 2(9.8)h

-651.24 = -19.6h

h = 651.24 / 19.6

h = 33.23 m

Thus, at 33.23 m the speed will be 12 m/s

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3 years ago

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