Here we can say that there is no external torque on this system
So here we can say that angular momentum is conserved
so here we will have

now we have



similarly let the final distance is "r"
so now we have


now from above equation we have


so final distance is 0.04 m between them
 
        
             
        
        
        
The steel would expand by 4. 8 * 10^-3 cm
<h3>How to determine the linear expansion</h3>
The change in length  ΔL is proportional to length  L. It is dependent on the temperature, substance, and length.
Using the formula:
ΔL= α LΔT
where  ΔL  is the change in length  L = 10cm
 ΔT  is the change in temperature = 60° - 20° = 40° C
  α  is the coefficient of linear expansion = 1.2 x 10^-5 °C
Substitute into the formula
ΔL = 
ΔL =  cm
 cm
Therefore, the steel would expand by 4. 8 * 10^-3 cm
Learn more about linear expansion here:
brainly.com/question/14325928
#SPJ1
 
        
             
        
        
        
Answer:
Distance = 85.3 miles
displacement = 0
Explanation:
The total distance covered to grandma's house is 42.6 miles as recorded by the odometer. The same distance would be covered when returning to the base. Hence;
Total distance for the round trip = 42.6 + 42.6 = 85.2 miles
Since the trip was a round trip, the displacement is zero because the family returned to their initial location.
 
        
             
        
        
        
Answer:
    P₁ = 2.3506 10⁵ Pa
Explanation:
For this exercise we use Bernoulli's equation and continuity, where point 1 is in the hose and point 2 in the nozzle
           P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
           A₁ v₁ = A₂ v₂
Let's look for the areas
           r₁ = d₁ / 2 = 2.25 / 2 = 1,125 cm
           r₂ = d₂ / 2 = 0.2 / 2 = 0.100 cm
           A₁ = π r₁²
           A₁ = π 1.125²
           A₁ = 3,976 cm²
           A₂ = π r₂²
           A₂ = π 0.1²
           A₂ = 0.0452 cm²
Now with the continuity equation we can look for the speed of water inside the hose
            v₁ = v₂ A₂ / A₁
            v₁ = 11.2 0.0452 / 3.976
            v₁ = 0.1273 m / s
Now we can use Bernoulli's equation, pa pressure at the nozzle is the air pressure (P₂ = Patm) the hose must be on the floor so the height is zero (y₁ = 0)
            P₁ + ½ ρ v₁² = Patm + ½ ρ v₂² + ρ g y₂
           P₁ = Patm + ½ ρ (v₂² - v₁²) + ρ g y₂
Let's calculate
            P₁ = 1.013 10⁵ + ½ 1000 (11.2² - 0.1273²) + 1000 9.8 7.25
            P₁ = 1.013 10⁵ + 6.271 10⁴ + 7.105 10⁴
            P₁ = 2.3506 10⁵ Pa