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Hitman42 [59]
3 years ago
5

What is simple machine

Physics
2 answers:
const2013 [10]3 years ago
6 0
Any of the basic mechanical devices for applying a force, such as an inclined plane, wedge, or lever.
vodka [1.7K]3 years ago
6 0

Hello!

Explanation:

↓↓↓↓↓↓↓↓↓↓↓↓

Simple machines have few or no moving parts. They make work easier.

  1. Inclined plane
  2. Wedge
  3. Screw
  4. Lever
  5. Wheel and axle
  6. Pulley

Inclined plane is a sloping surface, such as a ramp. Inclined plane make it easier to lift objects. The distance is greater, but the amount of force used is less. The amount of work done is the same. Wedge is used to split things apart. Force is applied to the large area of the wedge. The force is concentrated on a smaller area at the pointed end. The wedge looks like two inclined planes placed back to back. A screw can hold things together. The threading grips materials. The threading on a screw looks like an inclined plane spiraling around the outside of the screw. Large screw are also used to lift things. A car jack lifts a car by using a large screw. A lever is a strong bar that turns about a fulcrum, or fixed point. It can be used to lift heavy objects. Force applied at one end is transmitted to the other end. A lever can change the direction of a force. Moving the position of the fulcrum affects how much force is needed. A wheel and axle consists of two circular objects of different sizes that are connected. The smaller-diameter object, the axle, is a rod that goes through the wheel and lets the wheel turn. When the axle is turned, the wheel moves a greater distance, but less force is needed to move it. A pulley changes the direction of a force. A pulley consists of a grooved wheel and a rope. Pulling down on the rope lifts objects. A construction crane uses a series of pulleys. A flagpole has a pulley at the top.

Hope this helps!

Thank you for posting your question at here on brainly.

-Charlie

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Answer:2

Explanation:

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3 years ago
Is there any induced current in the pickup coil when the polarity of the bar magnet is flipped?
stiks02 [169]

Answer:

Faraday's law , he direction of the magnetic field changes by 180º, in the polarity inversion processes, induces a voltage.  

Explanation:

For this exercise let's use Faraday's law

          E = - dФ / dt

          Ф = B.A = B A cos θ

where B is the magnetic field, A is the area and θ is the angle between the field line and the normal to the area.

We can see that an electromotive force (voltage) is indexed when there is a variation of the field B, a variation of the area and change of the angle or when there is a combinational of them.

In this case, the magnitude of the field is constant, as the wire is rigid metal, the area is constant, but the direction of the magnetic field changes by 180º, in the polarity inversion processes, for which reason each change induces a voltage.

If a voltage is created in the ring, which has a resistance, a current is also generated in it.

Therefore the answer is If a current is created in the hoop

8 0
2 years ago
What force is required to accelerate a 1840 kg car from 4.77 m/s to 23.5 m/s,
neonofarm [45]
A :-) for this question , we should apply
a = v - u by t
Given - u = 4.77 m/s
v = 23.5 m/s
t = 5.18 m/s
Solution -
a = v - u by t
a = 23.5 - 4.77
a = 28.27 m/s^2

.:. The acceleration is 28.27 m/s^2
7 0
2 years ago
Which process do single-celled organisms go through to reproduce asexually?
andrezito [222]
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7 0
3 years ago
Freight car A with a gross weight of 200,000 lbs is moving along the horizontal track in a switching yard at 4 mi/hr. Freight ca
zhenek [66]

Answer: a) 4.7 mi/hr.  b) 86,500 lbs. mi²/Hr²

Explanation:

As in any collision, under the assumption that no external forces exist during the very small collision time, momentum must be conserved.

If the collision is fully inelastic, both masses continue coupled each other as a single mass, with a single speed.

So, we can write the following:

p₁ = p₂ ⇒m₁.v₁ + m₂.v₂ = (m₁ + m₂). vf

Replacing by the values, and solving for vf, we get:

vf = (200,000 lbs. 4 mi/hr + 100,000 lbs. 6 mi/hr) / 300,000 lbs = 4.7 mi/hr

If the track is horizontal, this means that thre is no change in gravitational potential energy, so any loss of energy must be kinetic energy.

Before the collision, the total kinetic energy of the system was the following:

K₁ = 1/2 (m₁.v₁² + m₂.v₂²) = 3,400,000 lbs. mi² / hr²

After the collision, total kinetic energy is as follows:

K₂ = 1/2 ((m₁ + m₂) vf²) = 3,313,500 lbs. mi²/hr²

So we have an Energy loss, equal to the difference between initial kinetic energy and final kinetic energy, as follows:

DE = K₁ - K₂ = 86,500 lbs. mi² / hr²

This loss is due to the impact, and is represented by the work done by friction forces (internal) during the impact.

8 0
3 years ago
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