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anygoal [31]
3 years ago
12

Chemical reaction precipitate for Ba (NO3)2+K2 CO3?

Chemistry
2 answers:
Alinara [238K]3 years ago
7 0
Yes, because the net ionic is equation will yield BaCO3 as a precipitate because it is insoluble in water
Sveta_85 [38]3 years ago
5 0

Ba(NO₃)₂+K₂CO₃→BaCO₃↓+2KNO₃

So, BaCO₃ is (white) precipitate

Open the solubility table, it says that barium carbonate is insoluble

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Muscle contraction is triggeredA) in response to an increase in the cytoplasmic Ca2+concentration.B) in response to a decrease i
natima [27]

Answer:

A) in response to an increase in the cytoplasmic Ca2+concentration.

Explanation:

Muscle contraction occurs in response to an increase in the cytoplasmic Ca2 + concentration.

This process occurs with the shortening of the sarcomeres resulting in a result, the actin filaments react with myosin, generating actomyosin. During this reaction, it is necessary to increase the cytoplasmic concentration of Ca + and ATP. In this, myosin will break down ATP, releasing energy so that the muscle can contract.

4 0
3 years ago
What is the excess reactant in the combustion of 23 g of methane in the open atmosphere?
Marta_Voda [28]

Answer : The excess reactant in the combustion of methane in opem atmosphere is O_{2} molecule.

Solution : Given,

Mass of methane = 23 g

Molar mass of methane = 16.04 g/mole

The Net balanced chemical reaction for combustion of methane is,

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

First we have to calculate the moles of methane.

\text{ Moles of methane}=\frac{\text{ Given mass of methane}}{\text{ Molar mass of methane}} = \frac{23g}{16.04g/mole} = 1.434 moles

From the above chemical reaction, we conclude that

1 mole of methane react with the 2 moles of oxygen

and 1.434 moles of methane react to give \frac{2moles\times 1.434moles}{1moles} moles of oxygen

The Moles of oxygen = 2.868 moles

Now we conclude that the moles of oxygen are more than the moles of methane.

Therefore, the excess reactant in the combustion of methane in open atmosphere is O_{2} molecule.


6 0
3 years ago
Suppose the flask is already at equilibrium but then the volume of the reaction flask is then reduced what will happen
sveta [45]

1) Answer is: c) The reaction will proceed right.

Balanced chemical reaction: N₂(g) + 3H₂(g) ⇄ 2NH₃(g) ΔH = +92 kJ.

Reducing the volume of the system increase the partial pressures of the products and reactants.

With a pressure increase due to a decrease in volume, the side of the equilibrium with fewer moles is more favorable, there are 4 moles at the left side (three moles of hydrogen and one mole of nitrogen) and 2 moles (ammonia) at the right side of the reaction.

2) Answer is: d) The partial pressure of ammonia will increase.

This reaction is endothermic (enthalpy is higher than zero), which means that heat is added.

According to Le Chatelier's principle when the reaction is endothermic heat is included as a reactant and when the temperature increased, the heat of the system increase, so the system consume some of that heat by shifting the equilibrium to the right,  producing more ammonia.

8 0
3 years ago
David kept 100 grams of radioactive sodium in a container. He observed the amount of sodium left in the container after regular
Anna [14]
First we have to understand what a half life is. A half life is a measure of time when the amount of a certain object is 50% of the original amount. Hence the answer for this is letter A. The initial amount is 100. fifty percent of 100 is 50 and that happens after 15 hours. Hence, 15 hours is the half life period. 
5 0
3 years ago
Read 2 more answers
Explain, in detail, how you convert grams of one substance to grams of something else. Be specific and include each step
elena-14-01-66 [18.8K]
I will present a simple reaction so we can do this conversion:

2H₂ + O₂ → 2H₂O

We will assume we have 32 g of O₂ and we want to find the amount of water, assuming this reaction goes to completion. We must first convert the initial mass to moles, which we do using the molar mass in units of g/mol. The molar mass of O₂ is 32 g/mol.

32 g O₂ ÷ 32 g/mol = 1 mole O₂.

Now that we have moles of oxygen, we use the molar coefficients to find the ratio of water molecules to oxygen molecules. We can see there are 2 moles of water for every 1 mole of oxygen.

1 moles O₂ x (2 mol H₂O/ 1 mol O₂) = 2 moles H₂O

Now that we have the moles of water, we can convert this amount into grams using the molar mass of water, which is 18 g/mol.

2 moles H₂O x 18 g/mol = 36 g H₂O

Now we have successfully converted the mass of one molecule to the mass of another.
5 0
3 years ago
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