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Vinil7 [7]
3 years ago
6

Based on its position on the periodic table, which of the following properties should beryllium (Be) have?

Chemistry
2 answers:
nadezda [96]3 years ago
8 0

Answer:

low melting point bcs its an earth metal

Explanation:

geniusboy [140]3 years ago
7 0
The answer is definitely A
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What was the oxygen crisis
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3 years ago
Is methylene chloride more or less dense than water?
horsena [70]
Methylene chloride is less dense than water
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3 years ago
If you hold a backpack in your hand, the force of gravity pulls it downward. What force keeps it from falling to the ground?
Deffense [45]

Answer:

The force of the gases pushes downward at the same time that the gases push the rocket upwards. 1.

Explanation:

7 0
2 years ago
Water is known as the universal solvent. One reason water makes a good solvent is because it is composed of polar molecules. Wha
Flauer [41]

Answer: Option (C) is the correct answer.

Explanation:

A water molecule is made up of two hydrogen atoms and one oxygen atom. Its molecular formula is H_{2}O.

It is known that hydrogen is electropositive in nature whereas oxygen is electronegative in nature. Therefore, oxygen will pull the electron of hydrogen towards itself as a result, there will be formation of partial positive charge on hydrogen and partial negative charge on oxygen atom.

Thus, the water molecule becomes polar. So, we can conclude that water molecule is a polar molecule because water molecules have a positive charge on one end and a negative charge on  the other.

5 0
2 years ago
The Lyman series results from excited state hydrogen atoms transiting to
Nutka1998 [239]

Answer:

I can't draw diagrams on this web site but I can do with numbers I think. So an electron is moved from n = 1 to n = 5. I'm assuming I've interpreted the problem correctly; if not you will need to make a correction. I'm assuming that you know the electron in the n = 1 state is the ground state so the 4th exited state moves it to the n = 5 level.

n = 5 4th excited state

n = 4 3rd excited state

n = 3 2nd excited state

n = 2 1st excited state

n = 1 ground state

Here are the possible spectral lines.

n = 5 to 4, n = 5 to 3, n = 5 to 2, n = 5 to 1 or 4 lines.

n = 4 to 3, 4 to 2, 4 to 1 = 3 lines

n = 3 to 2, 3 to 1 = 2 lines

n = 2 to 1 = 1 line. Add 'em up. I get 10.

b. The Lyman series is from whatever to n = 1. Count the above that end in n = 1.

c.The E for any level is -21.8E-19 Joules/n^2

To find the E for any transition (delta E) take E for upper n and subtract from the E for the lower n and that gives you delta E for the transition.

So for n = 5 to n = 1, use -Efor 5 -(-Efor 1) = + something which I'll leave for you. You could convert that to wavelength in meters with delta E = hc/wavelength. You might want to try it for the Balmer series (n ending in n = 2). I think the red line is about 650 nm.

Explanation:

8 0
2 years ago
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