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Zarrin [17]
3 years ago
14

You are on an alien planet where the names for substances and the units of measures are very unfamiliar.

Chemistry
1 answer:
enyata [817]3 years ago
8 0

Given that

1 skvarnick = 45 quibs

3 quibs = 7 sleps

Now if we have 45 quibs it means we have you have one skvarnick

three quibs = 7 sleps

so one quib = 7/3 sleps

so 45 quibs = 7 X 45 / 3 = 105 sleps

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Can someone help please
enyata [817]

Answer:

d. cells are made of atoms and molecules. :)

Explanation:

hope i helped

8 0
2 years ago
Read 2 more answers
An excess of Ba(No3)2 reacts with 250ml of H2SO4 solution to give 0.55g of BaSo4.determine The concentration in moles per litre
Wewaii [24]
Chemical reaction: Ba(NO₃)₂ + H₂SO₄ → BaSO₄ + 2HNO₃.
V(H₂SO₄) = 250 mL ÷ 1000 mL/L = 0,25 L.
m(BaSO₄) = 0,55 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,55 g ÷ 233,38 g/mol.
n(BaSO₄) = 0,00235 mol.
From chemical reaction: n(BaSO₄) : n(Ba(NO₃)₂) = 1 : 1.
n(Ba(NO₃)₂) = 0,00235 mol.
c(Ba(NO₃)₂) = n(Ba(NO₃)₂) ÷ V.
c(Ba(NO₃)₂) = 0,00235 mol ÷ 0,25 L.
c(Ba(NO₃)₂) = 0,0095 mol/L.
7 0
3 years ago
Do you guys know any cool app for revision apart from quiz let
hammer [34]
Kahoot, there are some pretty great reviews on there but you may need to do some searching
7 0
2 years ago
Why is NaNO3 a homogenous mixture in terms of particle arrangement/composition?
Fed [463]
<span> A homogeneous mixture is composed of a single visible phase while a heterogeneous mixture has two or more</span>
8 0
3 years ago
What is the molarity of a solution that contains 122g of MgSO4 n 3.5L of solution?​
Semmy [17]

Answer:

0.29mol/L or 0.29moldm⁻³

Explanation:

Given parameters:

Mass of MgSO₄ = 122g

Volume of solution = 3.5L

Molarity is simply the concentration of substances in a solution.

Molarity = number of moles/ Volume

>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.

Number of moles = mass/ molar mass

Molar mass of MgSO₄:

Atomic masses: Mg = 24g

S = 32g

O = 16g

Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol

= (24 + 32 + 64)g/mol

= 120g/mol

Number of moles = 122/120 = 1.02mol

>>>> From the given number of moles we can evaluate the Molarity using this equation:

Molarity = number of moles/ Volume

Molarity of MgSO₄ = 1.02mol/3.5L

= 0.29mol/L

IL = 1dm³

The Molarity of MgSO₄ = 0.29moldm⁻³

8 0
3 years ago
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