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SSSSS [86.1K]
4 years ago
6

The table below shows the average distances of Venus and Earth from the sun. -Name of Planet -Distance from the sun (in AU) Venu

s 0.72 Earth 1.0 What is the difference between the orbital periods of Venus and Earth? a. 1.72 years b. 1.62 years c. 0.62 years d. 0.28 years
Physics
2 answers:
Serhud [2]4 years ago
6 0
<span>Venus goes around faster than Earth, so its period must be less than Earths 1.0 years. That eliminates the first two answers. My recollection is that T^2 = k r^3, relating period of orbit to radius, so T should be (0.72/1.00)^3/2 = 0.61 of the Earths period, so 0.62 is ans. </span>
Paul [167]4 years ago
6 0

Answer: 0.39 years (Venus orbits the Sun in 0.62 Earth years)

Explanation:

The orbital period is related to the distance of the planet from the star as:

T² = R³

where T is in years and R is in AU.

<u>Orbital period of Venus:</u>

T² = (0.72)³

⇒ T = 0.62 years

<u>Orbital period of Earth </u>

T² = (1.0)³

⇒T = 1 year

The difference between the orbital periods of Venus and Earth is: (1 -0.62) = 0.38 years. Venus orbits the Sun in 0.62 Earth years.

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If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
White raven [17]

Answer:

400ft.    32ft/s       -32ft/s

Explanation:

In reality the gravitational acceleration is 9.81 so the quadratic coefficient of the function should be 9.81/2

Anyway for the sake of assumtion let us takes=160t-16t^2

 

ds/dt=160-32t=0

 

t=160/32= 5 seconds.

s=160*160/32-16*(160/32)^2= 400 mts

 

 

s=384 mts

160t-16t^2=384

i.e

16t^2-160t+384=0

 

t^2-10t+24=0

(t-6)(t-4)=0

t=[4,6]

we have to take t=4 because it is all the up i.e <5

 

velocity =v=ds/dt=160-32t

 

v=160-32*4=32 ft/sec still going up

 

for all the way down take t=6 whuch is >5

 

v=160-6*32=-32 ft/sec (falling down!!!)

6 0
3 years ago
Consider two antennas separated by 9.00 m that radiate in phase at 120 MHz, as described in Exercise 35.3. A receiver placed 150
alexgriva [62]

Answer:

\phi=4.52 rad

Explanation:

From the question we are told that

Distance b/e antenna's d=9.00m

Frequency of antenna RadiationF_r=120 MHz \approx 120*10^6Hz

Distance from receiver d_r=150m

Intensity of Receiver i= 10

Distance difference of the receiver b/w antenna's (r^2-r^1)=1.8m

Generally the equation for Phase difference \phi is mathematically given by

 \phi=\frac{2\pi}{\frac{c}{f_r}} *(r^2-r^1)

 \phi=\frac{2*\pi}{\frac{3*10^{8}}{120*10^6}} *1.8

 \phi=\frac{4\pi}{5}  *1.8

<h3>  \phi=4.52 rad</h3>

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\phi=4.52 rad

7 0
3 years ago
PLEASE HELP!!!!!
never [62]

Answer:

The answer is A

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When a rockets thrusters push on the ground the ground pushes back on the rocket with equal force in the opposite direction. Hence the rocket takes off.

Newtons third law of motion states, for every action there is an equal and opposite reaction.

7 0
2 years ago
Direct current, DC, flows in a _________ direction while alternating current, AC, the direction of flow ___________. A) single,
kramer
The flow of Direct current (DC) is constant and flows in one direction. Most digital electronics make use of DC. Alternating current (AC) periodically flows in reverse and is mostly used to deliver power to houses, buildings and the like. With that alone, you can already rule out A, C and D. 

The answer would then be B. constant, periodically reversing. 
4 0
3 years ago
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Readme [11.4K]

Answer:

(d) A strong electron-phonon interaction

Explanation:

Superconductivity -

The phenomenon of superconductivity is due to the attractive force between electrons from the exchange of the phonons that cause the bound pair of electrons known as cooper pairs .

A strong electron -phonon intercation is suitable condition for superconductivity and high resistance .

4 0
3 years ago
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