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Colt1911 [192]
3 years ago
8

Draw a circuit that uses the resistors listed below as well as a 12V battery source. For your circuit, determine (a) the total r

esistance, (b) the total current, and (c) the total voltage over the entire system.
Physics
1 answer:
Zepler [3.9K]3 years ago
5 0

Answer: hello your questions lacks the required resistor values therefore i will provide a general answer using an example

answer : a) 14 ohms  b) 0.86 amps   c) 10.32 V

Explanation:

Assuming the resistors are : 3 ohms , 4 ohms and 5 ohms

Voltage source = 12V

<u>Assuming that the Resistors are in series </u>

<u>a) Determine Total resistance </u>

Req = R1 + R2 + R3

       = 3 + 4 + 5 = 14 ohms

<u>b) Total current </u>

Ieq = V / Req

      = 12 / 14 =  0.86 amps

<u>c) The Total Voltage over the entire system </u>

Vt = ∑ Voltage drops

    = ( 0.86 * 3 ) + ( 0.86 * 4 ) + ( 0.86 * 5 )

    = 10.32 V

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The Steamboat Geyser in Yellowstone National Park shoots water into the air at 48.0 m/s. How
qwelly [4]

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

Given;

initial velocity of the water, u = 48 m/s

at maximum height the final velocity will be zero, v = 0

the water is going upwards, i.e in the negative direction of gravity, g = -9.8 m/s².

The maximum height reached by the water is calculated as follows;

v² = u² + 2gh

where;

h is the maximum height reached by the water

0 = u² + 2gh

0 = (48)² + ( 2 x -9.8 x h)

0 = 2304 - 19.6h

19.6h = 2304

h = 2304 / 19.6

h = 117.55 m

Therefore, the maximum height reached by the water is 117.55 m.

7 0
2 years ago
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What is the SI unit of pressure? A. g/cm3 B. the pascal C. the newton D. m/s2
sesenic [268]
The basic definition of pressure is force/area and the scientific community defined that as the Pascal (Pa).
6 0
3 years ago
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What is the work-energy theorem equation?
grin007 [14]

Answer:

W = Fd = KE =1/2mv²

Explanation:

not sure if that's what your looking for but i'm pretty sure this is it.

7 0
3 years ago
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The world's most powerful laser is the LFEX laser in Japan. It can produce a 2 petawatt(2×10^15W) laser pulse that last for 1 ps
kogti [31]

Answer:

2.82942\times 10^{24}\ W\m^2

Explanation:

d = Diameter of spot = 30 μm

r = Radius of spot = \frac{d}{2}=\frac{30}{2}=15\ mu m

P = Power of the laser = 2\times 10^{15}\ W

A = Area = \pi r^2

Intensity is given by

I=\frac{P}{A}\\\Rightarrow I=\frac{2\times 10^{15}}{\pi\times (15\times 10^{-6})^2}\\\Rightarrow I=2.82942\times 10^{24}\ W/m^2

The light intensity within this spot is 2.82942\times 10^{24}\ W/m^2

8 0
3 years ago
If 270 watts of power is used in 42 seconds, how much work was done<br>​
navik [9.2K]

Answer: W = 11340J

Explanation:

Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.

So this is the Formula: Power = Work / Time.

<u>Step 1:</u><em><u> Find the Formula</u></em>

P = W / T

<em><u> </u></em>

<u>Step 2: </u><u><em>Make W the subject of the equation.</em></u>

W = PT

<u>Step 3:</u><u> </u><u><em>Given.</em></u>

P = 270 Watts, T = 42 seconds

<u>Step 4:</u><u><em> Substitute these values into equation 2 .</em></u>

W = 270(42)

<u>Step 5:</u><u> </u><u><em>Simplify.</em></u>

W = 11340J

The amount of work done was 11340.

~I hope I helped you! :)~

4 0
3 years ago
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