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Colt1911 [192]
3 years ago
8

Draw a circuit that uses the resistors listed below as well as a 12V battery source. For your circuit, determine (a) the total r

esistance, (b) the total current, and (c) the total voltage over the entire system.
Physics
1 answer:
Zepler [3.9K]3 years ago
5 0

Answer: hello your questions lacks the required resistor values therefore i will provide a general answer using an example

answer : a) 14 ohms  b) 0.86 amps   c) 10.32 V

Explanation:

Assuming the resistors are : 3 ohms , 4 ohms and 5 ohms

Voltage source = 12V

<u>Assuming that the Resistors are in series </u>

<u>a) Determine Total resistance </u>

Req = R1 + R2 + R3

       = 3 + 4 + 5 = 14 ohms

<u>b) Total current </u>

Ieq = V / Req

      = 12 / 14 =  0.86 amps

<u>c) The Total Voltage over the entire system </u>

Vt = ∑ Voltage drops

    = ( 0.86 * 3 ) + ( 0.86 * 4 ) + ( 0.86 * 5 )

    = 10.32 V

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Why does the speed of sound vary depending on the medium through which it travels. in general?
avanturin [10]
Because it is how fast it goes and it depends on the speed
4 0
3 years ago
A 4.00 kg block is pushed along the ceiling with a constant applied force of 85.0 N that acts at an angle of 55.0 degrees with t
steposvetlana [31]

Answer:

0.35

Explanation:

According to Newton's second law;

\sum Fx = ma

Fm - Ff =ma

Fm is the moving force = Wsin theta

Fm = 4(9.8)sin55

Fm = 32.1N

Ff is the frictional force = nmgcos theta

Ff = n(4)(9.8)cos55

Ff = 22.48n

Acceleration a = 6.0m/s²

Substitute the given values into the formula and get the coefficient of friction

32.11-23.48n = 4(6)

32.11-24= 23.48n

8.11 = 23.48

n = 8.11/23.48

n = 0.35

Hence the coefficient of friction is 0.35

6 0
3 years ago
A bicyclist of mass 60kg supplies 340W of power while riding into a 5 m/s head wind. The frontal area of the cyclist and bicycle
NikAS [45]

Answer:

87.1 mph

Explanation:

We are given that

Mass,m=60 kg

Power,P=340 W

Speed,v=5 m/s

Area,A=0.344 m^2

Drag coefficient,C_d=0.88

Coefficient of rolling resistance,\mu_r=0.007

Friction force,f=\mu_rmg=0.007\times 60\times 9.8=4.1 N

Where g=9.8 m/s^2

Let speed of cyclist=v'

Drag force,F_d=\frac{1}{2}\rho_{air}AC_dv^2

Density of air,\rho_{air}=1.225 kg/m^3

F_d=\frac{1}{2}\times 1.225\times 0.344\times 0.88(5)^2=4.635N

Power,P=(F_d+f)\times v'

340=(4.1+4.635) v'=8.735v'

v'=\frac{340}{8.735}=38.9m/s

v'=87.1 mph

1 m=0.00062137 miles

1 hour=3600 s

7 0
3 years ago
What is the difference in the speed of sound on a warm day versus on a cold day?
seraphim [82]
The sun is bright and when its cold there is no sun
4 0
3 years ago
An underwater scuba diver sees the Sun at an apparent angle of 43.0° above the horizontal. What is the actual elevation angle of
Inessa05 [86]

Answer:

The actual elevation angle is 12.87 degrees

Explanation:

In the attachment you can clearly see the situation. The angle of elevation as seen for the scuba diver is shown in magenta, we conclude that \theta_2=90-43=47.

Using Snell's Law we can write:

n_1\sin(\theta_1)=n_2\sin(\theta_2)

\implies \sin(\theta_1)=\frac{n_2}{n_1}\sin(\theta_2),

Let's approximate the index of refraction of the air (medium 1 in the picture) to 1.

We thus have:

\sin(\theta_1)=n_2\sin(\theta_2)=1.333\sin(47)

\implies\theta_1=\arcsin[n_2\sin(\theta_2)]=\arcsin[1.333\sin(47)]\approx 77.13. Calling \alpha the actual angle of elevation, we get from the picture that \alpha=90-77.13=12.97

7 0
3 years ago
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