Draw a circuit that uses the resistors listed below as well as a 12V battery source. For your circuit, determine (a) the total r
1 answer:
Answer: hello your questions lacks the required resistor values therefore i will provide a general answer using an example
answer : a) 14 ohms b) 0.86 amps c) 10.32 V
Explanation:
Assuming the resistors are : 3 ohms , 4 ohms and 5 ohms
Voltage source = 12V
<u>Assuming that the Resistors are in series </u>
<u>a) Determine Total resistance </u>
Req = R1 + R2 + R3
= 3 + 4 + 5 = 14 ohms
<u>b) Total current </u>
Ieq = V / Req
= 12 / 14 = 0.86 amps
<u>c) The Total Voltage over the entire system </u>
Vt = ∑ Voltage drops
= ( 0.86 * 3 ) + ( 0.86 * 4 ) + ( 0.86 * 5 )
= 10.32 V
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a) 2.64 s
We can solve this part of the problem by using the following SUVAT equation:
where
s is the displacement of the stone
u is the initial velocity
t is the time
a is the acceleration
We must be careful to the signs of s, u and a. Taking upward as positive direction, we have:
- s (displacement) negative, since it is downward: so s = -75.0 m
- u (initial velocity) positive, since it is upward: +15.5 m/s
- a (acceleration) negative, since it is downward: so a= g = -9.8 m/s^2 (acceleration of gravity)
Substituting into the equation,
Solving the equation, we have two solutions: t = -5.80 s and t = 2.84 s. Since the negative solution has no physical meaning, the stone reaches the bottom of the cliff 2.64 s later.
b) 10.4 m/s
The speed of the stone when it reaches the bottom of the cliff can be calculated by using the equation:
where again, we must be careful to the signs of the various quantities:
- u (initial velocity) positive, since it is upward: +15.5 m/s
- a (acceleration) negative, since it is downward: so a = g = -9.8 m/s^2
Substituting t = 2.64 s, we find the final velocity of the stone:
where the negative sign means that the velocity is downward: so the speed is 10.4 m/s.
c) 4.11 s
In this case, we can use again the equation:
where
s is the displacement of the package
u is the initial velocity
t is the time
a is the acceleration
We have:
s = -105 m (vertical displacement of the package, downward so negative)
u = +5.40 m/s (initial velocity of the package, which is the same as the helicopter, upward so positive)
a = g = -9.8 m/s^2
Substituting into the equation,
Which gives two solutions: t = -5.21 s and t = 4.11 s. Again, we discard the first solution since it is negative, so the package reaches the ground after
t = 4.11 seconds.