Draw a circuit that uses the resistors listed below as well as a 12V battery source. For your circuit, determine (a) the total r
1 answer:
Answer: hello your questions lacks the required resistor values therefore i will provide a general answer using an example
answer : a) 14 ohms b) 0.86 amps c) 10.32 V
Explanation:
Assuming the resistors are : 3 ohms , 4 ohms and 5 ohms
Voltage source = 12V
<u>Assuming that the Resistors are in series </u>
<u>a) Determine Total resistance </u>
Req = R1 + R2 + R3
= 3 + 4 + 5 = 14 ohms
<u>b) Total current </u>
Ieq = V / Req
= 12 / 14 = 0.86 amps
<u>c) The Total Voltage over the entire system </u>
Vt = ∑ Voltage drops
= ( 0.86 * 3 ) + ( 0.86 * 4 ) + ( 0.86 * 5 )
= 10.32 V
You might be interested in
Answer:
(a) The package lands 682 meters horizontally ahead from the point the package was dropped from the plane
(b) The horizontal component = 39.0 m/s
The vertical component = 171.55 m/s
(c) The angle of impact is 77.19°
Explanation:
The parameters given are;
Velocity of the plane, vₓ = 39.0 m/s
Height of the plane above the ground, h = 1.50 × 10² m = 1,500 m
(a) The time, t, before the package hits the ground when dropped from the plane is given by the relation;
h = u·t + 1/2×g×t²
Where:
g = Acceleration due to gravity = 9.81 m/s²
u = Initial vertical velocity = 0 m/s
Hence;
1500 = 0×t + 1/2 × 9.81 × t² = 4.905·t²
∴ t = √(1500/4.905) = 17.49 s
The horizontal distance the package travels before landing = 17.49 × 39 ≈ 682 m
The package lands 682 meters horizontally ahead from the point the package was dropped from the plane
(b) The vertical velocity, , of the package just before landing is given by the relation;
² = u² + 2·g·h
u = 0 m/s
∴ ² = 0 + 2×9.81×1500 = 29430 m²/s²
= √29430 = 171.55 m/s
Hence the horizontal component = 39.0 m/s
The vertical component = 171.55 m/s
(c) The angle of impact, θ, is given as follows;
∴ θ = tan⁻¹(4.4) = 77.19°.