Certin, because they can be any two cards.
If those two are your only choices then the answer is
none of the above.
<em>Attached is a cumulative frequency table for your data.</em> If you take a look at the two tables given, the frequencies were not tallied properly. If the frequency column is wrong, then the cumulative frequency will be wrong.
The answer is then none of the above or find one that matches the table attached.
12. On addition, you can just combine like terms.
2v^3+(-v^3)=v^3
-v+v cancels each other out
8+(-3)=5
So you have v^3+5
14 On subtraction, you have to remember to distribute the negative sign so after you do that you have:
4h^3+3h+1+5h^3-6h+2
Then you can combine like terms
4h^3+5h^3=9h^3
3h-6h=-3h
1+2=3
So you end up with:
9h^3-3h+3
Hope that helps and feel free to ask any questions.
Answer:
what is P(A), the probability that the first student is a boy? 3/5
what is P(B), the probability that the second student is a girl? 3/4
what is P(A and B), the probability that the first student is a boy and the second student is a girl? 1/2
No, évents A and B are not independent events
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
Let the number = x
7x + 1 = 5x + 25 Subtract 5x from both sides.
7x - 5x + 1 = 5x - 5x + 25 Combine
2x + 1 = 25 Subtract 1 from both sides.
2x + 1 - 1 = 25-1 Combine
2x = 24 Divide by 2
2x/2 = 24/2
x = 12