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Maslowich
3 years ago
14

Assume that the turntable deccelerated during time Δt before reaching the final angular velocity ( Δt is the time interval betwe

en the moment when the top disk is dropped and the time that the disks begin to spin at the same angular velocity). What was the average torque, ⟨τ⟩, acting on the bottom disk due to friction with the record?
Physics
1 answer:
Zina [86]3 years ago
6 0

Answer:

See below...

Explanation:

Let’s express ⟨α⟩ in terms of ωi , ωf , and Δt. and torque in terms of It , ωi , ωf , and Δt.

STEP 1.  

The rate of change of angular velocity is Angular acceleration.  

The net change in angular velocity is Average angular acceleration divided by the elapsed time.

⟨α⟩ = ω f −ω i/Δt

STEP 2.

Torque is assumed this way

          dω

   τ = I ----

           dt

.

⟨τ ⟩ = I t (ω f −ω i )/Δt

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Calculate the Force required to give a bullet of mass 50 g an acceleration of 300 m/s2
NNADVOKAT [17]

Answer:

<h3>The answer is 15 N</h3>

Explanation:

The force acting on an object can be found by using the formula

<h3>Force = mass × acceleration</h3>

From the question

mass = 50 g = 0.05 kg

acceleration = 300 m/s²

We have

force = 0.05 × 300

We have the final answer as

<h3>15 N</h3>

Hope this helps you

7 0
3 years ago
in which of the following collisions would you expect the kinetic energy to be conserved? a. a bullet passes through a block of
Scorpion4ik [409]

An elastic collision is one in which the system does not experience a net loss of kinetic energy as a result of the collision. In elastic collisions, momentum and kinetic energy are both conserved.

<h3>Explain about the Elastic Collision?</h3>

A collision between two bodies in physics is referred to as an elastic collision if their combined kinetic energy stays constant. There is no net conversion of kinetic energy into other forms, such as heat, noise, or potential energy, in an ideal, fully elastic collision

An example of an elastic collision is when two balls collide at a pool table. It is an elastic collision when you throw a ball on the ground and it bounces back into your hand because there is no net change in the kinetic energy.

If there is no kinetic energy lost in the impact, the collision is said to be perfectly elastic. A collision is considered to be inelastic if any of the kinetic energy is converted to another kind of energy during the collision.

To learn more about Elastic Collision refer to:

brainly.com/question/7694106

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8 0
1 year ago
The temperature inside my refrigerator is about 4 degrees C. If I place a balloon in my fridge that initially has a temperature
maksim [4K]

v

Convert the given temperatures from celsius to kelvin since we are dealing with gas.

To convert to kelvin, add 273.15 to the temperature in celsius.

T1 = 22 + 273.15 = 295.15 k

T2 = 4 + 273.15 = 277.15 k

V1 = 0.5 L

Let's find the final volume (V2).

To solve for V2 apply Charles Law formula below:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

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1 year ago
How many Newtons of force does it take to move a 53 kilogram object?
Sidana [21]
519.75N

explanation: good luck on whatever assignment
3 0
3 years ago
To develop muscle tone, a woman lifts a 2.50 kg weight held in her hand. She uses her biceps muscle to flex the lower arm throug
Romashka [77]

To solve this problem we will use the concepts related to Torque as a function of the Force in proportion to the radius to which it is applied. In turn, we will use the concepts of energy expressed as Work, and which is described as the Torque's rate of change in proportion to angular displacement:

\tau = Fr

Where,

F = Force

r = Radius

Replacing we have that,

\tau = Fr

\tau = 21cm (\frac{1m}{100cm})* 550N

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The moment of inertia is given by 2.5kg of the weight in hand by the distance squared to the joint of the body of 24 cm, therefore

I = 0.25Kg\cdot m^2 +(2.5kg)(0.24m)^2

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Finally, angular acceleration is a result of the expression of torque by inertia, therefore

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\alpha = \frac{11.55}{0.394}

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PART B)

The work done is equivalent to the torque applied by the distance traveled by 60 °° in radians (\pi / 3), therefore

W = \tau \theta

W = 11.5* \frac{\pi}{3}

W = 12.09J

4 0
3 years ago
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