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podryga [215]
3 years ago
10

How do you know if a reaction is endothermic?

Chemistry
1 answer:
Vikentia [17]3 years ago
6 0
In an exothermic reaction, heat is produced along with products. But in endothermic reaction, heat is absorbed. If the number of products is less than the sum of the enthalpies of the reactants, the reaction will be exothermic. If the number of products is more than the sum of the enthalpies of the reactants, the reaction is endothermic.
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Battery acid has a density of 1.285 g/mL and contains 38.0% sulfuric acid by mass. The car battery contains 1.45 L of battery ac
larisa86 [58]

Answer: 708.2 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Given : 38 g of H_2SO_4 is dissolved in 100 g of solution.

Density of solution = 1.285 g/ml

Volume of solution = \frac{mass}{density}=\frac{100g}{1.285g/ml}=77.8ml

Thus if 77.8 ml of H_2SO_4 contains = 38 g of H_2SO_4

1.45L= 1450 ml of H_2SO_4 contains = \frac{38}{77.8}\times 1450=708.2 g of H_2SO_4

Therefore, the mass of the sulfuric acid in a car battery is 708.2 g

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3 years ago
What is it called when a gas is converted into a liquid
alex41 [277]
Your answer is probably
Vaporization point
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2 years ago
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I know the paper is blurry but can anyone explain any of the questions from 76-80?
Whitepunk [10]

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3 0
3 years ago
You need to make 10.0 L of 1.2 M KNO3. What molar ( concentration) would the potassium nitrate solution need to be if you were t
solniwko [45]

Answer:

2.5L [NaCl] concentrate needs to be 4.8 Molar solution before dilution to prep 10L of 1.2M KNO₃ solution.

Explanation:

Generally, moles of solute in solution before dilution must equal moles of solute after dilution.

By definition Molarity = moles solute/volume of solution in Liters

=> moles solute = Molarity x Volume (L)

Apply moles before dilution = moles after dilution ...

=> (Molarity X Volume)before dilution = (Molarity X Volume)after dilution

=> (M)(2.5L)before = (1.2M)(10.0L)after

=> Molarity of 2.5L concentrate = (1.2M)(10.0L)/(2.5L) = 4.8 Molar concentrate

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Salts is the correct awnser
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