Answer:
The average atomic weight = 121.7598 amu
Explanation:
The average atomic weight of natural occurring antimony can be calculated as follows :
To calculate the average atomic mass the percentage abundance must be converted to decimal.
121 Sb has a percentage abundance of 57.21%, the decimal format will be
57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .
123 Sb has a percentage abundance of 42.79%, the decimal format will be
42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .
Next step is multiplying the fractional abundance to it masses
121 Sb = 0.5721 × 120.904 = 69.169178400
123 Sb = 0.4279 × 122.904 = 52.590621600
The final step is adding the value to get the average atomic weight.
69.169178400 + 52.590621600 = 121.7598 amu
Answer:
The answer is
<h2>760.46 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass of ethanol = 600 g
density = 0.789 g/mL
It's volume is

We have the final answer as
<h3>760.46 mL</h3>
Hope this helps you
Answer:
14700J
Explanation:
From the question given, the following were obtained:
M = 100g
ΔT = 35° C
C = 4.2J/g °C
Q=?
The heat transferred can calculated for by using the following equation
Q = MCΔT
Q = 100 x 4.2 x 35
Q= 14700J