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Ganezh [65]
3 years ago
12

How many grams of nh3 can be produced from 3.72 mol of n2 and excess h2.

Chemistry
1 answer:
olganol [36]3 years ago
7 0
N₂       + 3H₂ ⇒ 2NH₃
1mol       :         2mol
3,72mol  :         7,44mol

n = 7,44mol
M = 17g/mol

m = n * M = 7,44mol * 17g/mol = 126,48g
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