Answer:
Kc for this reaction is 0.06825
Explanation:
Step 1: Data given
Number of moles formaldehyde CH2O = 0.055 moles
Volume = 500 mL = 0.500 L
At equilibrium, the CH2O(g) concentration = 0.051 mol
Step 2: The balanced equation
CH2O <=> H2 + CO
Step 3: Calculate the initial concentrations
Concentration = moles / volume
[CH2O] = 0.055 moles . 0.500 L
[CH2O] = 0.11 M
[H2] = 0M
[CO] = 0M
Step 4: The concentration at the equilibrium
[CH2O] = 0.11 - X M = 0.051 M
[H2] = XM
[CO] = XM
[CH2O] = 0.11 - X M = 0.051 M
X = 0.11 - 0.051 = 0.059
[H2] = XM = 0.059 M
[CO] = XM = 0.059 M
Step 5: Calculate Kc
Kc = [H2][CO]/[CHO]
Kc = (0.059 * 0.059) / 0.051
Kc = 0.06825
Kc for this reaction is 0.06825
Its reversible, soluble, <span>mass, density, color, boiling point, temperature, and volume. </span>
Answer:
i. Lead nitrate:
2Pb (NO3)2 Δ= 2PbO+4NO2+O2
ii. Potassium chlorate:
2KClO3 → 2KCl + 3O2↑
iii. clacium carbonate:
CaCO3 + 2HCl -> CaCl2 + CO2 + H2O
iv. cupric carbonate :
CuCO3 → CuO + CO2↑
Hope this helped
All the best!!
Answer:
Soil conservation is important because soil is crucial for many aspects of human life as it provides food, filters air and water and helps to decompose biological waste into nutrients for new plant life. Soil can be drained away or contaminated, destroying it for use. Soil conversation involves working to reduce contamination and depletion.
Explanation:
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Answer:
Chemical change
Explanation:
There are types of changes in nature namely: physical change and chemical change. A physical change is a change that does not alter the chemical composition of the substances involved, hence, no new substances are formed. On the other hand, a chemical change changes the chemical composition of the involved substances to form new substances.
Based on the definition of the types of changes below, the equation depicted in this question is a CHEMICAL CHANGE because it involves a rearrangement of the atoms of each element in the reactants to produce new sets of products with a new chemical formula.
C17H17ON3(s) + 2C4H6O3(l) → C21H21O5N(s) + 2C2H4O2(l)
