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3 years ago

Does litmus paper indicate if a liquid is a base?

Chemistry

2 answers:

KIM [24]3 years ago

4 0

Yes, I hope this helped

Ksivusya [100]3 years ago

4 0

When litmus paper comes in contact with a base it becomes colors such as shades of blue, purple, and pink

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An organic liquid is a mixture of methyl alcohol (CH3OH) and ethyl alcohol (C2H5OH). A 0.220-g sample of the liquid is burned in

Artist 52 [7]

Answer:

Mass of Methyl alcohol (or methanol) = 0.1403g

Explanation:

Step 1: Given data

Mass of Sample: ms = 0.220 g

Mass of CO2: m0 = 0.345 g

Mass of CH3OH = m1

Mass of C2H5OH = m2

Molar mass CO2 = 44.01 g/mole

Molar mass CH3OH = 32 g/mole

Molar mass C2H5OH 46.07 g/mole

Step 2: Tjhe balanced equation

2 CH3OH + 3 O2 = 2 CO2 + 4 H2O

C2H5OH + 3 O2 =2 CO2 + 3 H2O

------------------------------------------------------

2 CH3OH + C2H5OH + 6 O2 = 4 CO2 + 7 H2O

Step 3: Calculate mass

In the balanced equation we notice that , the amount of CO2 is related to the amount of the alcohols: Moles CO2 = 4

mass of CO2 = Molar mass CO2((mass CH3OH/ Molar mass CH3OH)+(mass C2H5OH/Molar mass C2H5OH))

mass of CO2 = 44.01 ((mass CH3OH/ 32.04) + (mass C2H5OH/ 46.07)

The sample has a mass of 0.220 g = mass CH3OH + mass C2H5OH

mass C2H5OH = 0.220G - mass CH3OH

This we will insert in the equation, so we will only have 1 unknown mass

0.345g = 44.01((m1/32.04) + (2(0.220-m1)/M2) )

<=> m1 = ((mCO2/44.01)-(2*0.22/46.07))÷((1/32.04)-(2/46.07))

Thus: m1 = ((0.345/44.01)-(2*0.220/46.07))÷((1/32.04)-(2/46.07))

Thus m1 = 0.1403 g = Mass of CH3OH

Since m2=(ms-m1).

m2 = 0.220-0.1403 = 0.0797 g = Mass of C2H5OH

Mass of methyl alcohol (Methanol) = 0.1403g

Mass of ethyl alcohol (Ethanol) = 0.0797g.

7 0

3 years ago

A 11.0 mLmL sample of 0.30 MHBrMHBr solution is titrated with 0.16 MNaOHMNaOH. Part A What volume of NaOHNaOH is required to rea

cupoosta [38]

Answer:

21 mL of NaOH is required.

Explanation:

Balanced reaction: $HBr+NaOH\rightarrow NaBr+H_{2}O$

Number of moles of HBr in 11.0 mL of 0.30 M HBr solution

= $(\frac{0.30}{1000}\times 11.0)$ moles = 0.0033 moles

Let's say V mL of 0.16 M NaOH solution is required to reach equivalence point.

So, number of moles of NaOH in V mL of 0.16 M NaOH solution

= $(\frac{0.16}{1000}\times V)$ moles = 0.00016V moles

According to balanced equation-

1 mol of HBr is neutralized by 1 mol of NaOH

So, 0.0033 moles of HBr are neutralized by 0.0033 moles of NaOH

Hence, $0.00016V=0.0033$

$\Rightarrow V=\frac{0.0033}{0.00016}=21$

So, 21 mL of NaOH is required.

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3 years ago

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d1i1m1o1n [39]

If im not mistaken plant cells go through a stage called photosynthesis meaning the cells can create it's own energy (food) off of water, Co2 and sunlight.

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Explanation:

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