1. Domain, kingdom, phylum, class, order, family, genus, species, and subspecies.
2. If a variety of the species with a certain gene is vulnerable to a specific disease, predator, or environmental development, other members of the species with variants of the gene may be better equipped to handle the problem, and the species won't die out, just a portion of the disadvantaged.
Answer:
5 meters per second squared
Explanation:
We calculate the acceleration using the formula:
a = (vf - vi) / t
where "vf" is the final velocity, "vi" the initial velocity, and "t" the time it took to change from the initial velocity to the final one.
In our case:
a = (45 - 5) / 8 = 40 / 8 = 5 m/s^2
Answer:
the mass of water is 0.3 Kg
Explanation:
since the container is well-insulated, the heat released by the copper is absorbed by the water , therefore:
Q water + Q copper = Q surroundings =0 (insulated)
Q water = - Q copper
since Q = m * c * ( T eq - Ti ) , where m = mass, c = specific heat, T eq = equilibrium temperature and Ti = initial temperature
and denoting w as water and co as copper :
m w * c w * (T eq - Tiw) = - m co * c co * (T eq - Ti co) = m co * c co * (T co - Ti eq)
m w = m co * c co * (T co - Ti eq) / [ c w * (T eq - Tiw) ]
We take the specific heat of water as c= 1 cal/g °C = 4.186 J/g °C . Also the specific heat of copper can be found in tables → at 25°C c co = 0.385 J/g°C
if we assume that both specific heats do not change during the process (or the change is insignificant)
m w = m co * c co * (T eq - Ti co) / [ c w * (T eq - Tiw) ]
m w= 1.80 kg * 0.385 J/g°C ( 150°C - 70°C) /( 4.186 J/g°C ( 70°C- 27°C))
m w= 0.3 kg
Answer:
1) 5.52 cm , C) 5.5 cm
Explanation:
When a measurement is carried out, in addition to the value of the magnitude, the error or uncertainty of the measurement must occur, in a direct measurement with an instrument the uncertainty is equal to the appreciation of the instrument.
Uniform see the errors by the number of significant figures days, in this cases they are two decimals for which the appreciation of the instrument ± - 0.01
now we can analyze the measurements made
1) 5.52 cm. Validate. It is a valid measurement is within the uncertainty range
2) 6.63 cm. It does not validate. It is out of the error range
3) 5.5 cm Valid. It is within the given error range,
4) 5.93 cm Not Valid. It is out of the error range.
Answer:
I say vehicle one, because both will apply the same amount of force but, because vehicle two has less mass, it will accelerate more rather than vehicle one which will accelerate less.
