A current-carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field. The magnetic field strength is 0.6 Tesla.
<h3>What is magnetic field?</h3>
The magnetic field is the region of space where an object experiences a magnetic force as it enters the field.
Given is the wire of length 50 cm = 0.5 m and the current is 10.0 A. There is a resultant force of 3.0 N on the wire due to the interaction of the current and field.
The relation between magnetic field strength and current is
F = ILB
Substituting 50 for L, 10 for I and 3 for F, we get the magnetic field strength B.
3 = 10 × 0.5 × B
B= 0.6 Tesla
Therefore, the magnetic field strength is 0.6 Tesla.
Learn more about magnetic field.
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Answer:
1.241 kg
Explanation:
The mass of the man in kg is 195 pound * (1/2.2) kg/pound = 195/2.2 = 88.64 kg
If 1.4% of the mass of a human body is calcium, then the mass of calcium inside the 88.64 kg man is
1.4% * 88.64 = 88.64*1.4/100 = 1.241 kg
So there's 1.241 kg of calcium inside a 195-pound man
Answer:
the string and metre rule
Explanation:
Answer:
6858.5712 m/s
Explanation:
Given that:
Radius, r
R = 3.20 * 10^3.
Normal force = 0.5 * normal weight
Normal force = Fn ; Normal weight = Fg
Fn = 0.5Fg
Recall:
mv² / R = Fn + Fg
Fn = 0.5Fg
mv² / R = 0.5Fg + Fg
mv² /R = 1.5Fg
mv² = 1.5Fg * R
F = mg
mv² = 1.5* mg * R
v² = 1.5gR
v = sqrt(1.5gR)
V = sqrt(1.5 * 9.8 * 3.2 * 10^3)
V = sqrt(47.04^3)
V = 6858.5712 m/s
