Answer:
1.400 mol
Explanation:
To convert grams to moles, you will need the molar mass. The molar mass of iron(iii) sulfate is 399.88 g/mol. Divide grams by the molar mass to find moles.
(560.0 g)/(399.88 g/mol) = 1.400 mol
There are 1.400 mol present in 560.0 g of iron(iii) sulfate.
Ammonia is NH3. The molar mass of NH3 is 17.0307g.
(1.2*10^3)/17.0307=70.46 moles of NH3.
If you are using significant figures, it is 70. moles of NH3.
Answer:- 324.3 grams.
Solution:- We have been given with 6.0 moles of nitrous acid and asked to calculate it's grams. Moles to grams is a unit conversion and for doing this conversion we multiply the given moles by the molar mass of the compound.
Molar mass is the formula mass and to calculate this the atomic masses of each atom are multiplied by their respective subscripts that is the number of the atom in the compound .
For example,
has one nitrogen atom and one oxygen atom. So, the molar mass of this is = atomic mass of N + 2(atomic mass of O)
= 14 + 2(16)
= 14 + 32
= 46 gram per mol
gram per mol is the unit of molar mass. So, the molar mass of
is 46 grams per mol.
Let's calculate the molar mass of nitrous acid using the same concept.
molar mass of [
= 1 + 14 + 2(16)
= 1 + 14 + 32
= 47 grams per mol
Now, 6.9 moles of nitrous acid could easily be converted to grams as:

= 324.3 g
Hence, the mass of 6.9 moles of nitrous acid is 324.3 grams.
Answer:
721 J
Step-by-step explanation:
At the bottom of its swing, all the potential energy of the pendulum has been converted to kinetic energy.
KE = 721 J
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<h3>
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