Through ratio and proportion, for every mole of O2, there is also a mole equivalent of CO2. In this case, we divide first 8.94 g O2 by 32 g/mol to convert the mass to mole. That is equivalent to 0.279375 mol which is also the amount of CO2. Multiplied by 44g/mol which is the molar mass of CO2, the answer is 12.29 grams CO2.
Answer:
Mass = 14.0 g
Explanation:
Given data:
Mass of mercury nitrate = 22.17 g
Mass of mercury formed = ?
Solution:
Chemical equation:
Hg(NO₃)₂ + 2K → 2KNO₃ + Hg
Number of moles of mercury nitrate:
Number of moles = mass/molar mass
Number of moles = 22.17 g / 324.6 g/mol
Number of moles = 0.07 mol
Now we will compare the moles of Hg(NO₃)₂ and mercury.
Hg(NO₃)₂ : Hg
1 : 1
0.07 : 0.07
Mass of mercury:
Mass = number of moles × molar mass
Mass = 0.07 mol × 200.6 g/mol
Mass = 14.0 g
Explanation:
The reaction is CaCO
3
+2HCl→CaCl
2
+H
2
O+CO
2
.
Thus, 2 moles of HCl reacts with one mole of calcium carbonate to produce one mole each of calcium chloride, water and carbon dioxide respectively.
Hence, 3 moles of HCl will react with excess of calcium carbonate to produce 3×
2
1
=1.5 mol of carbon dioxide
Answer:
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