Answer:
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The mass of plutonium that will remain after 1000 years if the initial amount is 5 g when the half life of plutonium-239 (239pu, pu-239) is 24,100 years is 2.5 g
The equation is Mr=Mi(1/2)^n
where n is the number of half-lives
Mr is the mass remaining after n half lives
Mi is the initial mass of the sample
To find n, the number of half-lives, divide the total time 1000 by the time of the half-life(24,100)
n=1000/24100=0.0414
So Mr=5x(1/2)^1=2.5 g
The mass remaining is 2.5 g
- The half life is the time in which the concentration of a substance decreases to half of the initial value.
Learn more about half life at:
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Answer is: the percent by mass of NaHCO₃ is 2,43%.
m(NaHCO₃) = 10 g.
V(H₂O) = 400 ml.
d(H₂O) = 1 g/ml.
m(H₂O) = V(H₂O) · d(H₂O).
m(H₂O) = 400 ml · 1 g/ml.
m(H₂O) = 400 g.
m(solution) = m(H₂O) + m(NaHCO₃).
m(solution) = 400 g + 10 g.
m(solution) = 410 g.
ω(NaHCO₃) = 10 g ÷ 410 g · 100%.
ω(NaHCO₃) = 2,43 %
Explanation:
(1) CuF2+Mg-------->MgF2+Cu
(2) 2Na+2H2O --------> 2NaOH+H2
(3) 2KBr+Cl2-------->2KCl+Br2
Answer: For this homework question, you’ll need to look up the molar mass of AgNO₃. Use this to calculate the number of moles in the sample.
Then note that silver is (quite usually) univalent, so there will be as many moles of AgCl as there were of AgNO₃.
Ask your instructor or tutor for more in-depth training, if need be. Good luck!
Explanation:
