Answer:
HgSO₄
Explanation:
% => g => moles => ratio => reduce => empirical ratio
%Hg = 67.6% => 67.6g/201g/mol = 0.34mol
%S = 10.8% => 10.8g/32g/mol = 0.34mol
%O = 21.6% => 21.6g/16g/mol = 1.35mol
Hg:S:O => 0.34:0.34:1.35
Reduce to whole number ratio by dividing by the smaller mole value...
Hg:S:O => 0.34/.34:0.34/.34:1.35/.34 => Empirical Ratio = 1:1:4
∴ Empirical Formula is HgSO₄
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Answer:
0.0705 moles NaClO
Explanation:
<em>Assuming the bleach solution are 100mL:</em>
First, we need to find the mass of the solution knowing density = 1.0g/mL:
100mL * (1g/mL) = 100g
Then, we must find the mass of NaClO in 100g of solution using its percentage by mass:
100g * (5.25g NaClO / 100g) = 5.25g NaClO
As the last point, we need to convert the mass to moles using molar mass of NaClO = 74.44g/mol:
5.25g NaClO * (1mol/74.44g) = 0.0705 moles NaClO
Answer: group 15
Explanation: I just answered the question and got it right