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timofeeve [1]
3 years ago
8

Please help thank you

Chemistry
1 answer:
puteri [66]3 years ago
6 0

Answer:

B) Polonium and Arsenic

Explanation:

Metalloids are a small category of elements that are right between metals and non-metals, and have properties from those categories.

The most recognized are: Boron, Silicon, Germanium, Arsenic,  Antimony, and Tellurium.

Some that are irregularly recognized are Polonium and Astatine.

The only option with the elements in either of the shown elements is B) Polonium and Arsenic.

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Which Group 15 element exists as diatomic molecules at STP?
ikadub [295]

Answer: The correct option is 2.

Explanation: Group 15 elements are Nitrogen, phosphorous, Arsenic, Antimony, Bismuth.

To know whether an element exits as a diatomic molecule or not, we look at the atomicity of an element.

Atomicity is the number of atoms of an element combining to form a molecule.

Atomicity of Nitrogen = 2

Atomicity of Phosphorous = 4

Atomicity of Bismuth = 1

Atomicity of Arsenic = 1

The element having atomicity 2 will exist as a diatomic molecule.

Hence, Nitrogen is a diatomic molecule (N_2)

4 0
3 years ago
Read 2 more answers
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
Savatey [412]

Answer:

The value of  the heat capacity of the Calorimeter  C_c = 54.4 \frac{J}{c}

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = m_w C_w ΔT + C_c ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This is the value of  the heat capacity of the Calorimeter.

5 0
3 years ago
What distinguishes a substance from a mixture?
wariber [46]
A mixture consists of numerous substances, whereas a substance does not consist of mixtures, but rather of compounds. Mixtures can be separated physically, while substances cannot.
4 0
4 years ago
In the following reaction 8 grams of ethane are burned and 11 grams of CO2 are collected. What is the percent yield? 2C2H6+7O2=
Alika [10]
47% yield.  
First, let's determine how many moles of ethane was used and how many moles of CO2 produced. Start with the respective atomic weights. 
Atomic weight carbon = 12.0107 
Atomic weight hydrogen = 1.00794 
Atomic weight oxygen = 15.999  
Molar mass C2H6 = 2 * 12.0107 + 6 * 1.00794 = 30.06904 g/mol 
Molar mass CO2 = 12.0107 + 2 * 15.999 = 44.0087 g/mol  
Moles C2H6 = 8 g / 30.06904 g/mol = 0.266054387 mol 
Moles CO2 = 11 g / 44.0087 g/mol = 0.249950578 mol  
Looking at the balanced equation, for every 2 moles of C2H6 consumed, 4 moles of CO2 should be produced. So at 100% yield, we should have 0.266054387 / 2 * 4 = 0.532108774 moles of CO2. But we only have 0.249950578 moles, or 0.249950578 / 0.532108774 = 0.46973587 =
46.973587% of what was expected.  
Rounding to 2 significant figures gives 47% yield.
8 0
4 years ago
What are substances that have the same composition, but different structures, known as?
dimulka [17.4K]
The answer is Allotropes.
8 0
4 years ago
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