Answer:
Explanation:
Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation. slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)
Explanation;
According to Arrhenius equation:
i.e. ln(k2/k1) = -Ea/R (1/T2 - 1/T1)
Where, k1 = 0.000717, T1 = 45 oC = (45+273) K = 318 K
T2 = 25 oC = (25 + 273) K = 298 K
i.e. ln(k2/0.000717) = -12070 (1/298 - 1/318)
i.e. ln(k2/0.000717) = -2.54738
i.e. k2/0.000717 = 
= 0.078286
Therefore, the required constant (k2) = 0.078286 * 0.000717 = 
A physical change is a change to a sample of matter in which some properties of the material change, but the identity of the matter does not. Physical changes can further be classified as reversible or irreversible. The melted ice cube may be refrozen, so melting is a reversible physical change.
The molar mass of a 0.314-gram sample of gas having a volume of 1.6 l at 287 k and 0.92 atm. is 5.23 gram.
<h3>What is an Ideal Gas ?</h3>
An Ideal Gas is a law for ideal gas which states that the product of Pressure and Volume is equal to the product of the moles of sample, universal gas constant and temperature.
PV = nRT
The given data in the question is
Pressure = 0.92 atm
Volume = 1.6 l
Temperature = 287 K
0.92 * 1.6 = n * 287 * 0.082
n = 0.06 moles
0.06 = 0.314 / molecular weight
molecular weight = 0.314/0.06
Molecular weight = 5.23 gm
Molar mass = 5.23 gm.
The temperature and pressure conditions at which the gas behaves like an ideal gas is 273 K and 1 atm.
To know more about Ideal Gas
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Answer:
i would but there is nothing to awnser soooo!!! sorry
Explanation:
Answer:
C
Explanation:
it is genetics of the environment
