<u>Answer:</u> Step 2 in the given mechanism is the rate determining step
<u>Explanation:</u>
In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.
The intermediate reaction of the mechanism follows:
<u>Step 1:</u> 
<u>Step 2:</u> 
As, step 2 is the slow step. It is the rate determining step
Rate law for the reaction follows:
![\text{Rate}=k[O_3][O]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BO_3%5D%5BO%5D)
Hence, step 2 in the given mechanism is the rate determining step
Answer:
HNO3(aq) + OH-(aq) → NO3-(aq) + H2O(l)
Explanation:
According to Bronsted-Lowry theory, an acid is a substance that donates a proton (H+) and produces a conjugate base while a base is a molecule or ion which accepts the proton.
An example of Bronsted-Lowry acid and base is Nitric acid, HNO3 and hydroxide ion, OH- respectively as shown in the given reaction.
Thus, the nitric acid acts as an acid by donating a proton to the hydroxide ion which accepts it, thus producing nitrate ion, NO3- as a conjugate base, while OH- produces H2O as a conjugate acid.
Explanation:
The formula mass of a molecule (also known as formula weight) is the sum of the atomic weights of the atoms in the empirical formula of the compound.
a. NO2
N = 14
O = 16
NO2 = 14 + (16 * 2) = 46 amu
b. C4H10
Empirical formular = C2H5
C = 12
H = 1
C2H5 = (12*1) + (1*5) = 12 + 5 = 17 amu
c. C6H12O6
Empirical formular = CH2O
C = 12
H = 1
O = 16
C2H5 = 12 + (1*2) + 16 = 30 amu
d MgBr2
Mg = 24
Br = 80
MgBr2 = 24 + (80*2) = 184 amu
e. HNO2
H = 1
N= 14
0 = 16
HNO2 = 1 + 14 + (16*2) = 47 amu
f. CBr4
C= 12
Br = 80
CBr4 = 12 + (80*4) = 332 amu
g. Cr(NO3)3
Cr = 52
N = 14
O = 16
Cr(NO3)3 = 52 + 3[14 + (3*16)] = 238 amu
Explanation:
The prefix trans- and its variant tra- mean "across".
A translucent substance allows some light to go "across" it to the other side. Also, think about a transparent substance: it allows light to go "across" it; or a translation, it is a going "across" from one language into another.
