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shutvik [7]
3 years ago
7

If something is 6 square feet, what is the length and width of the poster?

Mathematics
1 answer:
Alex777 [14]3 years ago
7 0
Length is 2 and width is 3 

2 X 3 is 6
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Luna entered a raffle for a new pair of running shoes. She purchased 20 tickets and was told that she had a 20% chance of winnin
xenn [34]

Answer:

<h3>100 tickets</h3>

Step-by-step explanation:

Probability of winning = amount of tickets purchased/Total number of tickets

20% = 20/total number of tickets

20/100 = 20/total number of tickets

cross multiply

20 * total number of tickets = 20 * 100

20 *  total number of tickets = 100

total number of tickets sold = 100 tickets

6 0
3 years ago
Read 2 more answers
Solve: x³-7x²+36=0.​
Aliun [14]

Answer:

3,6,-2

Step-by-step explanation:

a+2a+b = 7

2a^2b = -36

a*2a + ab + 2ab = 0

or, a(2a+3b) = 0

so, b = -2a/3

Solve those and you find 3,6,-2

3 0
3 years ago
Could you please help me for this question?
Olin [163]

Answer:

  See attached for graphs

  g(x) -- domain: -∞ < x < ∞; range: 0 < y < ∞

  g^-1(x) -- domain: 0 < x < ∞; range: -∞ < y < ∞

Step-by-step explanation:

g(x) is an exponential decay function. Its base is 1/3, so each increase of 1 unit in x will multiply the y-value by a factor of 1/3. The graph will rapidly approach its horizontal asymptote of y=0 as x gets large. The y-intercept is (0, 1). Just as y gets smaller as x increases, so it gets larger as x decreases. Each decrease of x by 1 unit causes the y-value to be multiplied by 3.

__

The graph of g^-1(x) is the graph of g(x) reflected across the line y=x. That is, each coordinate pair (x, y) on the graph of g(x) becomes a point (y, x) on the graph of the inverse function. In order to graph g^-1(x), you don't need to write down the function, you only need to know the relationship between the graphs.

Just as x- and y- are interchanged on the graph, so the domain, range, and intercepts are interchanged. g^-1(x) will have a vertical asymptote of x=0, and an x-intercept of (1, 0). The domain of g^-1(x) is the range of g(x): 0 < x < ∞; and the range of g^-1(x) is the domain of g(x): -∞ < y < ∞.

__

The attached graph shows g(x) in red and g^-1(x) in blue. As you can see, we created the graph simply by interchanging x and y. The line y=x is shown for reference, so you can see that each curve is a reflection of the other across that line.

_____

<em>Additional comment</em>

The explicit expression for g^-1(x) can be found by solving for y:

  x = g(y)

  x=\left(\dfrac{1}{3}\right)^y=\dfrac{1}{3^y}=3^{-y}\\\\ \log(x)=-y\cdot\log(3)\qquad\text{take logarithms}\\\\y=-\dfrac{\log{x}}{\log{3}}=-\log_3{x}\qquad\text{use the change of base relation}\\\\\boxed{g^{-1}(x)=-\log_3{x}}

If you're familiar with the log function, you know it has an x-intercept of 1 and a vertical asymptote at x=0. The base of the log function is simply a vertical scale factor. The minus sign reflects it across the x-axis.

6 0
2 years ago
How do you solve inequalites
zhenek [66]
<span>Many simple inequalities can be solved by adding, subtracting, multiplying or dividing both sides until you are left with the variable on its own.But these things will change direction of the inequality: ...<span>Don't multiply or divide by a variable (unless you know it is always positive or always negative)</span></span>
7 0
3 years ago
Is this correct???? TYSM
vfiekz [6]

Yep, this is all correct!

-6/2 = y/4

y = (-6×4)/2

y = -24/2

y = -12


x was multiplied by 2

and y was also multiplied by 2

5 0
3 years ago
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