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3 years ago

Solve: 1 - 2k += = -3k

Mathematics

2 answers:

enot [183]3 years ago

6 0

Answer:

k = -1

Step-by-step explanation:

1 - 2k = -3k

-2k +3k = -1

k = -1

MariettaO [177]3 years ago

3 0

Answer:

-1

Step-by-step explanation:

1-2k=-3k

1-2k+2k=-3k+2k

1=-1k

1/-1=-1k/-1

-1=k

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Precalculus

kodGreya [7K]

Answer:

$24.35

Step-by-step explanation:

We will use the compound interest formula provided to solve this problem:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, change 1% into a decimal:

1% -> $\frac{1}{100}$ -> 0.01

Since the interest is compounded monthly, we will use 12 for n. Lets plug in the values now:

$A=800(1+\frac{0.01}{12})^{12(3)}$

$A=824.35$

Lastly, subtract A from the principal to get the interest earned:

$824.35 - 800 = 24.35$

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3 years ago

Use the diagram to answer the question.

Aloiza [94]

Answer:

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3 years ago

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masya89 [10]

if you mean.

$6 \leqslant \frac{4u}{ - 9}$

then the answer would be,

$u \leqslant - \frac{27}{2}$

7 0

3 years ago

Read 2 more answers

Let U = {q, r, s, t, u, V, W, x, y, z}

Alexus [3.1K]

Answer:

B'=U-B={q, r, s, t, u, V, W, x, y, z}-{q, s, y, z}={r,t, u, V, W, x, y}

A'=U-A={q, r, s, t, u, V, W, x, y, z}-{q, s, u, w, y}={r,t,v,w,x,z}

B'UC={r,t, u, V,W, x, y}U{v, w, x, y, z).={{r,t, u, V,W, x, y,z}

Step-by-step explanation:

(B'U C) U A'={{r,t, u, V,W, x,y,z}U{r,t,v,w,x,z}={{r,t, u, V,W, x,y,z}

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3 years ago

What is the solution to the system of equations graphed below?

Anna35 [415]

Answer: b

Step-by-step explanation:

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