What concept explains why some objects heat up faster than others when exposed to the same heat source?

The equivalence point of a titration corresponds to which of the following?

lorasvet [3.4K]

Answer:

E: the point where the acid and base have been added in proper stoichiometric amounts

Explanation:

Equivalence point in titration is simply the point where the amounts of acid and base used just sufficiently reacts chemically to cause neutralization whereas the endpoint is the point where the indicator of the titration changes colour.

The Equivalence point occurs before the endpoint.

Thus, option E is correct.

7 0

4 years ago

What is not a typical step when performing scientific research

Gelneren [198K]

The six steps of the scientific are:

1. State the question

2. Conduct research

3. Create a hypothesis

4. Perform the experiment

5. Analyze the data

6. Conclusion

So D. would be the correct answer, even though communicating the results could possibly be a step if it's required.

8 0

3 years ago

You are given a sulfuric acid solution of unknown concentration. You dispense 10.00 mL of the unknown solution into an Erlenmeye

dmitriy555 [2]

Answer:

"0.053457 M" of sulfuric acid.

Explanation:

The given values are:

$V$ = 10 mL solution

$V_{added}$ = 12.20 mL

$V_{total}$ = 22.20 mL

then,

M 0.103 M of NaOH,

$V_{rinsed}$ = experiment will not be affected

$V_{total \ base}$ = 10.38 mL

Now,

⇒ mol of NAOH = MV

= $0.103\times 10.38$

= $1.06914 \ m$

Whether Sulfuric acid, then

⇒ $H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O$

⇒ $mol \ of \ acid =\frac{1}{2}\times \ mol \ of \ base$

⇒ $1.06914 \ m \ mol \ of \ base = \frac{1}{2}\times 1.06914 = 0.53457 \ m \ mol \ of \ acid$

Before any dilution:

$V_{sample} = 10 \ mL$

⇒ $M \ acid = \frac{m \ mol}{V}$

$=\frac{ 0.53457 }{10}$

$=0.053457 \ M$ (Sulfuric acid)

6 0

3 years ago

Please help I’ll mark brainliest. Thank you :)

Jobisdone [24]

Answer:

a. There are only 5 electrons in 2p. 2p should be filled with 6 electrons prior to 3s and 3p

b. There are 8 electrons in 2p. 2p should be filled only with 6 electrons (not 8)

Explanation:

The typical electron configuration: 1s2 2s2 2p6 3s2 3p6

a. There are only 5 electrons in 2p

=> should be 1s2 2s2 2p6 3s2 3p2

b. There are 8 electrons in 2p

=> should be 1s2 2s2 2p6 3s2 3p1

6 0

2 years ago

Geraniol, C10H17OH, is an rose-scented alcohol commonly used in perfumes. How many grams of geraniol should be added to 600. mL

Maksim231197 [3]

Answer:

215.12 g

Explanation:

The change in the bolling temperature is a collateral property called ebullioscopy. The elevation on temperature occurs because there'll be a solute in the pure compound, and that solute(generally non-volatile) has a different boiling point, so the total bolling pint should increase.

To calculate the elevation in the temperature, we must use the Raoult equation:

ΔT = KbxWxi

Where ΔT is the variation of the temperature of boiling point, Kb is the

ebullioscopy constant, W is the molarity, and i the Vant' Hoff factor, which for molecules is also equal to 1, because they don't form ions. So:

82.00 - 78.40 = 1.22xW

W = 3.60/1.22

W = 2.9508

The molarity can also be calculated by:

$W = \frac{m1}{M1xm2}$

Where m1 is the mass of the solute (in grames), M1 is the molar mass of the solute, and m2 is the mass of the solvent (in kg).

The density of ethanol is 0.789 g/cm³, and 1 mL = 1 cm³, so 600.00 mL = 600.00 cm³ :

0.789 = m2/600

m2 = 473.4 g = 0.4734 kg

The molar mass of geraniol is:

C: 12 g/mol x 10 = 120 g/mol

H: 1 g/mol x 18 = 18 g/mol

O: 16 g/mol x 1 = 16 g/mol

M1 = 154 g/mol

Then:

$2.9508 = \frac{m1}{154x0.4734}$

m1 = 215.12 g of geraniol.

7 0

4 years ago