Above question is incomplete. Complete question is attached below
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Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.
In present case,
reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is
least reactive.
On other hand,
reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is
most reactive.
<em><u>Question</u></em>
<em><u>What </u></em><em><u>does </u></em><em><u>it </u></em><em><u>mean </u></em><em><u>to </u></em><em><u>optimize</u></em><em><u> </u></em><em><u>a </u></em><em><u>solution?</u></em>
<em><u>To find out best possible solution for a given problem within the given constraint is generally termed as optimization</u></em>
<em><u>How </u></em><em><u>are </u></em><em><u>solution</u></em><em><u> </u></em><em><u>optimize</u></em><em><u> </u></em><em><u>?</u></em>
<em><u>To solve an optimization problem, begin by drawing a picture and introducing variables. Find an equation relating the variables. Find a function of one variable to describe the quantity that is to be minimized or maximized. Look for critical points to locate local extrema.</u></em>
Answer:
1400KJ/mol⁻¹
Explanation:
Amount of heat required can be found by:
Q = m × c × ΔT
<em>Where m is the mass, c is the specific heat capacity (4.2KJ for water) and ΔT is the change in temperature.</em>
Q = 24 × 4.2 × (23 - 9)
= 24 × 4.2 × 14
= 1411.2KJ/mol⁻¹
= <u>1400KJ/mol⁻¹</u> (to 2 significant figures)
Answer:
Tc^(+7) - 2.35*10^-5M
PO4(^-3) - 5.50*10^-5M
Explanation:
Tc3(PO4)7 <---> 
1 mol 3 mol 7 mol
7.85 X 10^-6 M 3*7.85*10^-6M 7*7.85*10^-6M
2.35*10^-5M 5.50*10^-5M
Explanation:
- It is known that the amount of heat necessary to raise the temperature of 1 gram of a substance by
is known as specific heat.
Since, q = 
So, larger is the specific heat of a substance less will be the change in its temperature.
Therefore, olive oil has less specific heat as compared to water. This means that olive oil would get hotter.
- Similarly, the specific heat of gold is lesser than the given materials or metals. Hence, gold will requires less heat to rise its temperature.
As a result, water present in gold will heat readily.
- As the relation between heat and specific heat is as follows.
q = 
Therefore, calculate the amount of heat required by the water as follows.
q = 
= 
= 33440 J
or, = 33.44 kJ (as 1 kJ = 1000 J)
Thus, 33.44 kJ heat would it take to raise the temperature of 100.0 g of water from
to
.