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Romashka [77]
3 years ago
9

Using the reaction: Mg + O2 --> Mgo,

Chemistry
1 answer:
blondinia [14]3 years ago
6 0

Answer:

2Mg +O2 -----》 2MgO

the balanced equation

if you start with 2g of Mg let's calculate moles

one mole of mg id 24.30 g

so number of moles =0.08

hence 2 moles of Mg reacts with 1 mole of O2 molecule

so Moles of O2 molecule is 0.04

and mass of O2 in gm is = 16 ×0.04

which is equal to 0.64 gm

so the conclusion is if you start with 2g Mg, you need 0.64 grams of

O2 molecules for this reaction to go to

completion!!

i d k it's right or wrong but i tried my best :)

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just olya [345]
Above question is incomplete. Complete question is attached below
........................................................................................................................
Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.

In present case, reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is least reactive.

On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive. 


7 0
4 years ago
What does it mean to optimize a solution ?<br> How are solutions optimize
Romashka [77]

<em><u>Question</u></em>

<em><u>What </u></em><em><u>does </u></em><em><u>it </u></em><em><u>mean </u></em><em><u>to </u></em><em><u>optimize</u></em><em><u> </u></em><em><u>a </u></em><em><u>solution?</u></em>

<em><u>To find out best possible solution for a given problem within the given constraint is generally termed as optimization</u></em>

<em><u>How </u></em><em><u>are </u></em><em><u>solution</u></em><em><u> </u></em><em><u>optimize</u></em><em><u> </u></em><em><u>?</u></em>

<em><u>To solve an optimization problem, begin by drawing a picture and introducing variables. Find an equation relating the variables. Find a function of one variable to describe the quantity that is to be minimized or maximized. Look for critical points to locate local extrema.</u></em>

6 0
3 years ago
Calculate the amount of heat required to raise the temperature of a 24 g sample of water from 9°C to 23°C.
borishaifa [10]

Answer:

1400KJ/mol⁻¹

Explanation:

Amount of heat required can be found by:

Q = m × c × ΔT

<em>Where m is the mass, c is the specific heat capacity (4.2KJ for water) and ΔT is the change in temperature.</em>

Q = 24 × 4.2 × (23 - 9)

= 24 × 4.2 × 14

=   1411.2KJ/mol⁻¹

= <u>1400KJ/mol⁻¹</u>  (to 2 significant figures)

7 0
3 years ago
What is the concentration of each ion in 15.00 ml of a 7.85 X 10^-6 M solution of Tc3 (PO4)7?
Daniel [21]

Answer:

Tc^(+7)    -    2.35*10^-5M  

PO4(^-3)  -   5.50*10^-5M

Explanation:

Tc3(PO4)7  <--->              3Tc^{7+} + 7PO_{4}^{3-}

1 mol                                3 mol      7 mol

7.85 X 10^-6 M    3*7.85*10^-6M       7*7.85*10^-6M

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5 0
3 years ago
Specific Heat Material Copper Aluminum Gold Pyrex Specific Heat (J/g °C) 0.385 0.902 0.129 0.75 Material Water Ice Olive Oil Air
zimovet [89]

Explanation:

  • It is known that the amount of heat necessary to raise the temperature of 1 gram of a substance by 1^{o}C is known as specific heat.

Since,     q = mC \Delta T

So, larger is the specific heat of a substance less will be the change in its temperature.

Therefore, olive oil has less specific heat as compared to water. This means that olive oil would get hotter.

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As a result, water present in gold will heat readily.

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3 0
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