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LenaWriter [7]
4 years ago
11

Wet-cell batteries are typically used to supply eletrical energy to

Mathematics
1 answer:
o-na [289]4 years ago
4 0
Wet-cell batteries are typically used for AUTOMOBILES.
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If the perimeter of a rhombus is 164 and the length of the longer diagonal is 80, find the length of the shorter diagonal.
AysviL [449]

A rhombus has four equal sides. If the perimeter of this rhombus is 164, then the length of one side is 164/4, or 41.


Draw this rhombus. Label all four sides with "41." Label the longer diagonal 80 and the half length of that diagonal 40. You will see inside the rhombus four congruent triangles with hypotenuse 41, leg 10 and unknown height. Thus, this unknown height is found by solving x^2 + 40^2 = 41^2, and x^2=9, so that the length of the shorter diagonal is 2(2) = 18 (answer).

6 0
4 years ago
Samuel filled the glasses shown below completely with water. The total amount of water that Samuel poured into the glasses is 60
Rama09 [41]
The height of the cylinder (glass 1) we call h so the volume is 4πh cc.
The volume of the cone is ⅓×2.5²×6π=12.5π cc.
If we divide 60 by π we get 19.11 cc approx.
So 4h+12.5=19.11, 4h=6.61 cc and h=1.7 cm approx, answer 2.
3 0
4 years ago
Read 2 more answers
Maria, Carolina and Pedro receives $1600 from their grandfather in ratio 7:5:4. calculate share of each.
Nimfa-mama [501]

Step-by-step explanation:

<em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>total</em><em> </em><em>money </em><em>received</em><em> </em><em>by </em><em>them </em><em>=</em><em> </em><em>$</em><em>1</em><em>6</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>the </em><em>given </em><em>ratio </em><em>are </em><em> </em><em>7</em><em>:</em><em>5</em><em>:</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>let </em><em>the </em><em>ratio </em><em>be </em><em>X </em><em>,</em><em>now</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>Maria </em><em>=</em><em> </em><em>7</em><em>X</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>Carolina</em><em> </em><em>=</em><em> </em><em>5</em><em>X</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>Pedro </em><em>=</em><em> </em><em>4</em><em>X</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>w</em><em>e </em><em>know </em><em>whole </em><em>money </em><em>=</em><em> </em><em>$</em><em>1</em><em>6</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>so,</em><em> </em><em>adding</em><em> </em><em>all </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em>. </em><em>7</em><em>x</em><em> </em><em>+</em><em> </em><em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>4</em><em>x</em><em> </em><em>=</em><em> </em><em>$</em><em>1</em><em>6</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>1</em><em>6</em><em>x</em><em> </em><em>=</em><em> </em><em>$</em><em>1</em><em>6</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em> </em><em>x=</em><em> </em><em>$</em><em>1</em><em>6</em><em>0</em><em>0</em><em>/</em><em>1</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em>. </em><em>x </em><em>=</em><em> </em><em>$</em><em>1</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>now </em><em>Maria</em><em> </em><em>=</em><em> </em><em>7</em><em>*</em><em>1</em><em>0</em><em>0</em><em> </em><em>=</em><em> </em><em>$</em><em>7</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Carolina</em><em> </em><em>=</em><em> </em><em>5</em><em>*</em><em>1</em><em>0</em><em>0</em><em> </em><em>=</em><em> </em><em>$</em><em>5</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>Pedro</em><em> </em><em>=</em><em> </em><em>4</em><em>*</em><em>1</em><em>0</em><em>0</em><em> </em><em>=</em><em> </em><em>$</em><em>4</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em>hope it</em><em> helps</em>

8 0
3 years ago
There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc
sergeinik [125]

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and  B be the event that student play soccer.

P(A)=8\%

P(B)=14\%

It is given that 6 students play on both teams.

P(A\cap B)=\frac{6}{200}\times 100=3\%

We have to find the probability that a student plays either basketball or soccer.

P(A\cup B)=P(A)+P(B)-(A\cap B)

P(A\cup B)=8\%+14\%-3\%

P(A\cup B)=19\%

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

6 0
4 years ago
A card is drawn from a standard deck of 52 playing cards. Find the probability that the card is a four or a queen
laiz [17]
8/52 have a great day
3 0
3 years ago
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