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Leviafan [203]
3 years ago
6

Plsss help me!!! ASAP!!!

Chemistry
1 answer:
Arisa [49]3 years ago
8 0

Answer:

I think the answer is D...

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Which of the following is not part of our solar system?
andreyandreev [35.5K]

Answer:

none of the above

Explanation:

4 0
2 years ago
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a solution must be at a higher temperature than a pure solvent to boil. what colligative property can be employed to achieve thi
Kazeer [188]

Boiling-point elavation.

6 0
3 years ago
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2. A sample of neon gas has a volume of 87.6 L at STP. How many moles are present?
PSYCHO15rus [73]

Answer:

                      3.91 moles of Neon

Explanation:

According to Avogadro's Law, same volume of any gas at standard temperature (273.15 K or O °C) and pressure (1 atm) will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

                 n = moles = <u>???</u>

                 V = Volume = 87.6 L

Solution:

               As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

                          = ( 1 mole × 87.6 L) ÷ 22.4 L

                          = 3.91 moles

<h3>2nd Method:</h3>

                     Assuming that the gas is acting ideally, hence, applying ideal gas equation.

                              P V  =  n R T      ∴  R  =  0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹

Solving for n,

                              n  =  P V / R T

Putting values,

                              n  =  (1 atm × 87.6 L)/(0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹ × 273.15K)

                              n  =  3.91 moles

Result:

          87.6 L of Neon gas will contain 3.91 moles at standard temperature and pressure.

7 0
3 years ago
Volume of water displaced = 0.175 L Mass g Density g/cm3 Hardness: = Determine the unknown mineral. Unknown mineral: 7​
erastovalidia [21]

Answer:

Mass: 981.0 g

Density: 5.61 g/cm^3

Hardness: = 2.5 - 3

Unknown material: Chalcocite

Explanation:

5 0
3 years ago
What is the pH of a 6.4*10-10 m oh- solution?
egoroff_w [7]
PH: 4.80617997
pOH: 9.1938200
[H+]: 1.562
[OH-] 6.4E-10
Acid
8 0
3 years ago
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