Answer:
0.324 g is required to make 5.00 M solution of NaCl in 0.800 L.
Given data:
Molarity = 5.00 M
Formula Mass = 58.5 g/mol
Required volume = 0.800 L
To Find;
Mass in gram = ?
Solution:
Formula for calculating mass in gram is given as,
Mass in gram = Molarity × Formula mass × Volume required / 1000 putting values
Mass in gram = 5.00 M × 58.5 g/mol × 0.800 L / 1000
Mass in gram = 0.234 g
To find the empirical formula you would first need to find the moles of each element:
58.8g/ 12.0g = 4.9 mol C
9.9g/ 1.0g = 9.9 mol H
31.4g/ 16.0g = 1.96 O
Then you divide by the smallest number of moles of each:
4.9/1.96 = 2.5
9.9/1.96 = 6
1.96/1.96 = 1
Since there is 2.5, you find the least number that makes each moles a whole number which is 2.
So the empirical formula is C5H12O2.
Answer:
the color of the litmus paper will turn into blue color because sodium carbonate is basic in nature
Molar mass NO₂ = 46.0 g/mol
1 mole -------- 46.0 g
2.0 moles ----- ?
Mass (NO₂) = 2.0 x 46.0 / 1
=> 92.0 g
hope this helps!
It is C 2 1 2 1
You have to 1st balance the nitrates then balance the silvers to get the coefficients
